A synchronous clock problem in a rigid frame with constant proper acceleration
I am a beginner of general relativity. I read and follow the notation in <PERSON> book, Relativity Made Relatively Easy, chap 9.2. Suppose there is an rigid accelerating frame with constant proper acceleration with respect to inertial frame then the motion of grids of the frame is a set of hyperbolas. 1002
There is a relationship between inertial coordinate and Rindler frame: (Suppose $c=1$)
$$ \begin{cases} t=h\sinh(\theta)\ x=h\cosh(\theta) \end{cases} $$ , where $(t, x)$ are inertial frame coordinates and $(h, \theta)$ are the hyperbolic coordinates. The coordinate lines are hyperbola. $\theta$ is a measure of local time (not local proper time).
Now there is a light signal sent from $h_0$ to $h_1$ then and there is a mirror at $h_1$ and once the signal arrives at $h_1$ it is immediately reflected back to $h_0.$
The calculations of both trips are:
$$ \begin{cases} (h_0\sinh(\theta_0),h_0\cosh(\theta_0))+(\Delta t,\Delta t)=(h_1\sinh(\theta),h_1\cosh(\theta))\ (h_1\sinh(\theta),h_1\cosh(\theta))+(\Delta t,-\Delta t)=(h_0\sinh(\theta_1),h_0\cosh(\theta_1)) \end{cases} $$
I got two relationships:
$$ e^{\theta-\theta_0}=\frac{h_1}{h_0}\rightarrow\theta-\theta_0=\ln(\frac{h_1}{h_0})\ e^{\theta_1-\theta}=\frac{h_1}{h_0}\rightarrow\theta_1-\theta=\ln(\frac{h_1}{h_0}) $$
So the round-trip time is independent when the light is sent and the time is the same in both direction.
Now if there are three observers with equal distance in the accelerating frame ($h_1-h_0=h_2-h_1$), and they send light to the middle observer at their 12:00pm according to their local clock
Then I got a conclusion from the above calculation that the middle observer does not get synchronous signals, because
$$ \theta_2-\theta_1=\ln(\frac{h_2}{h_1}) \neq\theta_1-\theta_0=\ln(\frac{h_1}{h_0}) $$
which also means the clocks at $h_0$ and $h_2$ are not synchronous. However, according to my intuition, I know the grids are rigid, speed of light is a constant, and those two observers remain the same distance with the middle one and according to the diagram, those local clocks should be synchronous so the middle observer should receive synchronous signals in this experiment .
So what did I do it wrong here?
Thanks for your patience 272