Yes. Any interaction! Entenglement is only a quantum version of correlation. Let supose that you have two $\frac{1}{2}$ spins that interact one to another via magnetic interaction. This interaction can produce an entenglement. But this is not the only one. Some Amount of electrons are entangled in a metal due electrodynamic interaction.
You can produce entenglement by apply measurements to. In the case of two spins, the entenglement cam be produce by measuring the total angular momentum of the system. In this case, the correlation is made because if you know the state of one particle, this yields the knowledge of the other spin. In classical mechanics this is trivial because if you know the state of the whole system you can determine the state of the subsystems.
In quantum mechanics this is not always true. The total angular momentum $J^2$ don't commute with any projection of the spins $\vec{S}^{(1)}$ and $\vec{S}^{(2)}$. This imply that we can't divide the state of the system in the state of the parts when we have peculiar states (entangled states). Only the sum of the projections commute with the total angular momentum. In this case, the entangled states are $|1,0\rangle$ and $|0,0\rangle$ and the non-entangled states are $|1,-1\rangle$ and $|1,+1\rangle$, with has a trivial correlation as the classical ones.
We have:
$$ |0,0\rangle =\frac{|+,-\rangle -|-,+\rangle}{\sqrt 2} $$ $$ |1,0\rangle =\frac{|+,-\rangle + |-,+\rangle}{\sqrt 2} $$ $$ |1,-1\rangle =|-,-\rangle $$ $$ |1,+1\rangle =|+,+\rangle $$
Note that the non-trivial states (entangled) are superpositions of the $Sz^{(1)}$ and $Sz^{(2)}$ eigenvectors. 976
This superposition tells us that we can't define either the system are in $|+,-\rangle$ or in $|-,+\rangle$. We can only determine the probabilities of this possible measurement.
Now, if you apply some interaction in one spin, the other spin don't feel nothing! For example: if you measure the spin of one particle in the state $|0,0\rangle$, YOU know the spin of the other. Only this. Because the measurement, $J^2$ is not defined anymore and you can define a spin for each particle now. Using the correlation, if you measure +, then the other is -. But nothing actually happens in the other side! A quantum state is only a matemathical object that describe your state of knowledge about the system. And quantum mechanics is not realistc, so this state of knowledge is actually the final word. We don't get any thing "deep" that accounts this features. Quantum mechanics is subjective in this sense.
If we put another observer in the other side, in any way he can determine if you measeure or not by local operations. He needs to act on both spins for determine if you measure or not. As any other correlation. But a weird one, since is combine with some quantum features. This features is only feelled when we are doing things in both spins. You may find in some self studing that this quantum correlations violate some inequalities obeyed by classical correlations.
Entanglement is only a suitable combination of usual correlation and complementarity principle. 28