Using Ruffini's method we will find only one root ("x" = 3); factoring it out gives us "P"("x") = ("x"4 + 3"x"2 + 2)("x" − 3).
Using Ruffini's method we will find only one root ("x" = 3); factoring it out gives us "P"("x") = ("x"4 + 3"x"2 + 2)("x" − 3).