A right hexagonal prism has a height of 3 feet and each edge of the hexagonal bases is 6 inches. What is the sum of the areas of the non-hexagonal faces of the prism, in square feet?

[asy]import three;

currentprojection=orthographic(1/2,-1,1/2);

draw((0,0,0)--(1,0,0)--(1.5,0.86,0)--(1,1.72,0)--(0,1.72,0)--(-0.5,0.86,0)--cycle);

draw((0,0,6)--(1,0,6)--(1.5,0.86,6)--(1,1.72,6)--(0,1.72,6)--(-0.5,0.86,6)--cycle);

draw((0,0,0)--(0,0,6));

draw((1,0,0)--(1,0,6));

draw((1.5,0.86,0)--(1.5,0.86,6));

draw((1,1.72,0)--(1,1.72,6));

draw((0,1.72,0)--(0,1.72,6));

draw((-0.5,0.86,0)--(-0.5,0.86,6));

[/asy]
Since each non-hexagonal face is a rectangle with base 6 inches and height 3 feet, each face has an area of $6$ inches $\times 3$ feet $= .5$ feet $\times 3$ feet $= 1.5$ square feet per face.  Since there are 6 faces (6 edges to a hexagon), that makes for a total area of $\boxed{9}$ square feet.