The graph of $y = f(x)$ passes through the point $(-3,5).$  If $f(x)$ is an odd function, then what other point must the graph pass through?  Enter your answer as an ordered pair.
Since $f(x)$ is an odd function, $f(-x) = -f(x).$  In particular,
\[f(3) = -f(-3) = -5.\]Therefore, the graph of $f(x)$ must also pass through the point $\boxed{(3,-5)}.$

Also,
\[f(0) = -f(0),\]so $f(0) = 0.$  Thus, $\boxed{(0,0)}$ is also an acceptable answer.  (This is assuming that $f(x)$ is defined at $x = 0.$)