A greeting card is 6 inches wide and 8 inches tall. Point A is 3 inches from the fold, as shown. As the card is opened to an angle of 45 degrees, through how many more inches than point A does point B travel? Express your answer as a common fraction in terms of $\pi$. [asy]
import olympiad; import geometry; size(150); defaultpen(linewidth(0.8));
draw((0,0)--(6,0)--(6,8)--(0,8)--cycle);
filldraw((0,0)--(5,-1)--(5,7)--(0,8)--cycle,fillpen=white);

pair A = 0.5*((0,8)+(5,7));
label("$A$",A,SW);
dot((5,7));
dot(A); label("$B$",(5,7),SW);
label("$8''$",(0,0)--(0,8),W);label("$6''$",(0,0)--(5,-1),S);
point C = (2.5,3.5);
label(rotate(-aTan(1/5))*scale(0.8)*"Happy Birthday!",C);
[/asy]
Point A is traveling along the circumference of a circle with a diameter of 6 inches. This circumference is $6\pi$ inches.  Point B is traveling along the circumference of a circle with a diameter of 12 inches. This circumference is $12\pi$ inches. Both points travel 45 degrees, which is $45 \div 360 = 1/8$ of the circles' circumferences. The difference is then $(1/8)(12\pi) - (1/8)(6\pi) = (1/8)(12\pi - 6\pi) = (1/8)(6\pi) = \boxed{\frac{3}{4}\pi\text{ inches}}$.