problem: What is the sum of the next two terms in the geometric sequence 1, $\frac{1}{2}$, $\frac{1}{4}$, $\frac{1}{8}$, $\ldots$? Express your answer as a common fraction.
solution: The next two terms are $1/16$ and $1/32$. Their sum is $\frac{1}{16}+\frac{1}{32}=\frac{2}{32}+\frac{1}{32}=\boxed{\frac{3}{32}}$.