Calen originally had 5 more pencils than does Caleb, and Caleb has 3 less than twice as many pencils as does Candy.  If Calen lost 10 pencils, which left him with 10 pencils, then how many pencils does Candy have?
Calen originally had [NUMBER] more pencils than does Caleb, and Caleb has [NUMBER] less than twice as many pencils as does Candy. If Calen lost [NUMBER] pencils, which left him with [NUMBER] pencils, then how many pencils does Candy have?
If Calen lost 10 pencils, which left him with 10 pencils, then Calen originally had 10+10=<<10+10=20>>20 pencils.
Calen originally had 5 more pencils than does Caleb, and thus Caleb has 20-5=<<20-5=15>>15 pencils.
Let's let "x" represent the number of pencils owned by Candy.
Since Caleb has 3 less than twice as many pencils as does Candy, then (2*x)-3=15.
This simplifies to 2*x=18.
Thus, the number of pencils owned by Candy is x=<<9=9>>9 pencils.
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