Linda is painting her bedroom. Her bedroom has 4 walls, with the room being 20 feet wide by 20 feet long by 8 feet tall. One wall has a 3-foot by 7-foot doorway. A second wall has a 6-foot by 4-foot window. A third wall has a 5-foot by 7-foot doorway to a walk-in-closet. And the fourth wall is completely solid. What is the total area of wall space that Linda will have to paint?
The solid wall is 8 ft. * 20 ft. = <<8*20=160>>160 sq. ft.
The doorway is 3 ft. * 7 ft. = <<3*7=21>>21 sq. ft.
The window is 6 ft. * 4 ft. = <<6*4=24>>24 sq. ft.
The closet door is 5 ft. * 7 ft. = <<5*7=35>>35 sq. ft.
The total area of the doors and windows is 21 sq. ft + 24 sq. ft. + 35 sq. ft. = <<21+24+35=80>>80 sq. ft.
The solid wall is 160 sq. ft., so before the areas of the doors and window are taken into account, the total wall area is 4 * 160 sq. ft. = <<4*160=640>>640 sq. ft.
Taking into account the doors and window, the total wall area Linda will have to paint is 640 sq. ft. - 80 sq. ft. = <<640-80=560>>560 sq. ft.
#### 560
Below is an instruction that describes a task. Write a response that appropriately completes the request.

### Instruction:
You are solving math problems. Here are some examples of how to solve the task:

Colin can skip at six times the speed that Brandon can.  Brandon can skip at one-third the speed that Tony can.  And Tony can skip at twice the speed that Bruce can.  At what speed, in miles per hour, can Colin skip if Bruce skips at 1 mile per hour?Tony can skip at twice the speed that Bruce can, for a speed of 1*2=<<1*2=2>>2 miles per hour.
Brandon can skip at one-third the speed that Tony can, for a speed of 2*(1/3) = 2/3 miles per hour.
Colin can skip at six times the speed that Brandon can, for a speed of (2/3*6=4 miles per hour).
#### 4[END]

The cheerleading coach is ordering new uniforms. There are 4 cheerleaders who need a size 2, a certain number who need a size 6, and half that number who need a size 12. If there are 19 cheerleaders total, how many cheerleaders need a size 6?Let s be the number of cheerleaders who need a size 6 and t be the number who need a size 12. We know that s = 2t and s + t + 4 = 19.
Substituting the first equation into the second equation, we get 2t + t + 4 = 19
Combining like terms, we get 3t + 4 = 19
Subtracting 4 from both sides, we get 3t = 15
Dividing both sides by 3, we get t = 5
Substituting that value back into the equation s = 2t, we get s = 2 * 5 = <<2*5=10>>10
#### 10[END]

Now, solve this next question in the style of the above examples:

Linda is painting her bedroom. Her bedroom has 4 walls, with the room being 20 feet wide by 20 feet long by 8 feet tall. One wall has a 3-foot by 7-foot doorway. A second wall has a 6-foot by 4-foot window. A third wall has a 5-foot by 7-foot doorway to a walk-in-closet. And the fourth wall is completely solid. What is the total area of wall space that Linda will have to paint?

### Response:
The solid wall is 8 ft. * 20 ft. = <<8*20=160>>160 sq. ft.
The doorway is 3 ft. * 7 ft. = <<3*7=21>>21 sq. ft.
The window is 6 ft. * 4 ft. = <<6*4=24>>24 sq. ft.
The closet door is 5 ft. * 7 ft. = <<5*7=35>>35 sq. ft.
The total area of the doors and windows is 21 sq. ft + 24 sq. ft. + 35 sq. ft. = <<21+24+35=80>>80 sq. ft.
The solid wall is 160 sq. ft., so before the areas of the doors and window are taken into account, the total wall area is 4 * 160 sq. ft. = <<4*160=640>>640 sq. ft.
Taking into account the doors and window, the total wall area Linda will have to paint is 640 sq. ft. - 80 sq. ft. = <<640-80=560>>560 sq. ft.
#### 560