A road has four intersections. At the first intersection, there are 40 road signs showing different types of information mounted on the street poles. At the second intersection, 1/4 times more road signs than the first intersection are mounted on the street poles. The number of road signs at the third intersection is twice the number at the second intersection. If at the fourth intersection the number of road signs is 20 fewer than those at the third intersection, calculate the total number of road signs at the four intersections.
There are 1/4*40 = <<1/4*40=10>>10 more road signs at the second intersection than the first intersection.
This means there are 40+10 =<<40+10=50>>50 road signs at the second intersection.
The total number of road signs at the first and second intersection is 50+40 = <<50+40=90>>90
The third intersection has twice the number of road signs at the second intersection, meaning there are 2*50 = <<2*50=100>>100 road signs.
The total number of road signs at first to the third intersection is 90+100 = <<90+100=190>>190 road signs.
At the fourth intersection, the number is 20 fewer than at the third intersection, meaning there are 100-20 = <<100-20=80>>80 road signs.
All four road intersections have 190+80 = <<190+80=270>>270 road signs in total.
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Below is an instruction that describes a task. Write a response that appropriately completes the request.

### Instruction:
You are solving math problems. Here are some examples of how to solve the task:

Agatha has $60 to spend on a new bike. She spends $15 on the frame, and $25 on the front wheel. What does she have left, in dollars, to spend on a seat and handlebar tape?Agatha spends 15+25=<<15+25=40>>40 dollars.
Agatha has 60-40=<<60-40=20>>20 dollars left.
#### 20[END]

In Rodrigo's classroom in the morning there are red chairs, yellow chairs, and blue chairs. There are 4 red chairs. There are 2 times as many yellow chairs as red chairs, and there are 2 fewer blue chairs than yellow chairs. In the afternoon, Lisa borrows 3 chairs.  How many chairs are left in Rodrigo's classroom?There are 2 * 4 red chairs = <<2*4=8>>8 yellow chairs.
There are 8 yellow chairs - 2 = <<8-2=6>>6 blue chairs.
Total in the morning there were 4 red + 8 yellow + 6 blue = <<4+8+6=18>>18 chairs.
After Lisa removed chairs there were 18 - 3 chairs = <<18-3=15>>15 chairs remaining.
#### 15[END]

Now, solve this next question in the style of the above examples:

A road has four intersections. At the first intersection, there are 40 road signs showing different types of information mounted on the street poles. At the second intersection, 1/4 times more road signs than the first intersection are mounted on the street poles. The number of road signs at the third intersection is twice the number at the second intersection. If at the fourth intersection the number of road signs is 20 fewer than those at the third intersection, calculate the total number of road signs at the four intersections.

### Response:
There are 1/4*40 = <<1/4*40=10>>10 more road signs at the second intersection than the first intersection.
This means there are 40+10 =<<40+10=50>>50 road signs at the second intersection.
The total number of road signs at the first and second intersection is 50+40 = <<50+40=90>>90
The third intersection has twice the number of road signs at the second intersection, meaning there are 2*50 = <<2*50=100>>100 road signs.
The total number of road signs at first to the third intersection is 90+100 = <<90+100=190>>190 road signs.
At the fourth intersection, the number is 20 fewer than at the third intersection, meaning there are 100-20 = <<100-20=80>>80 road signs.
All four road intersections have 190+80 = <<190+80=270>>270 road signs in total.
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