In today's field day challenge, the 4th graders were competing against the 5th graders.  Each grade had 2 different classes.  The first 4th grade class had 12 girls and 13 boys.  The second 4th grade class had 15 girls and 11 boys.  The first 5th grade class had 9 girls and 13 boys while the second 5th grade class had 10 girls and 11 boys.  In total, how many more boys were competing than girls?
When you add up all the girls from all 4 classes, you had 12+15+9+10= <<12+15+9+10=46>>46 girls
When you add up all the boys from all 4 classes, you had 13+11+13+11 = <<13+11+13+11=48>>48 boys
There are 48 boys and 36 girls so 48-46 = 2 more boys
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Below is an instruction that describes a task. Write a response that appropriately completes the request.

### Instruction:
You are solving math problems. Here are some examples of how to solve the task:

Christi saw twice as many black bears as white bears and 40 more brown bears than black bears in a national park. If the number of black bears in the park is 60, calculate the population of bears in the park.If there are 60 black bears in the park and 40 more brown bears than black bears, there are 60+40 = <<60+40=100>>100 brown bears.
The number of black and brown bears in the park is 100+60 = <<100+60=160>>160
Twice the number of black bears as white bears means 60/2 = <<60/2=30>>30 white bears.
The population of bears in the national park is 30+160 = <<30+160=190>>190
#### 190[END]

At the bake sale, Tamara makes $32 from the brownies. She made 2 pans of brownies which were all sold.  The brownies were cut into 8 big square pieces.  How much did each brownie cost?Tamara had 2 x 8 = <<2*8=16>>16 big square brownie pieces.
Each brownie piece cost $32 / 16 = $<<32/16=2>>2.
#### 2[END]

Now, solve this next question in the style of the above examples:

In today's field day challenge, the 4th graders were competing against the 5th graders.  Each grade had 2 different classes.  The first 4th grade class had 12 girls and 13 boys.  The second 4th grade class had 15 girls and 11 boys.  The first 5th grade class had 9 girls and 13 boys while the second 5th grade class had 10 girls and 11 boys.  In total, how many more boys were competing than girls?

### Response:
When you add up all the girls from all 4 classes, you had 12+15+9+10= <<12+15+9+10=46>>46 girls
When you add up all the boys from all 4 classes, you had 13+11+13+11 = <<13+11+13+11=48>>48 boys
There are 48 boys and 36 girls so 48-46 = 2 more boys
#### 2