 Then, if the LSB were flipped from 1 to 0, then the next bit is also flipped.This goes on until finally a bit is flipped from 0 to 1, at which point the flipping stops.If the counter initially ends in "k" 1 bits, we flip a total of "k"+1 bits, taking actual time "k"+1 and reducing the potential by "k"−1, so the amortized time is 2.