 This particular spanning set is also a basis.If (−1, 0, 0) were replaced by (1, 0, 0), it would also form the canonical basis of R3.Another spanning set for the same space is given by {(1, 2, 3), (0, 1, 2), (−1, , 3), (1, 1, 1)}, but this set is not a basis, because it is linearly dependent.