Let's divide 12527 by 68
Let's see how many times 68 fits into 12527.

Step 1:
The number 68 fits into 1 0 times, leaving a remainder of 1.
The next digit of our result is 0. 
Result so far: 0.0
The remainder is 1 after subtracting 0 from 1.
Bring next digit (2) of the dividend behind the 1 and repeat the process: 12 / 68

Step 2:
12 divided by 68 is 0 with a remainder of 12.
Use 0 as the next digit of our solution. 
Result so far: 0.0
Deduct 0 from 12 and we're left with 12.
Append the next digit (5) from the dividend to 12 and continue with: 125 / 68

Let's proceed to step 3:
The number 68 fits into 125 1 times, leaving a remainder of 57.
The next digit of our result is 1. 
Result so far: 1.0
If we subtract 68 from 125, we get 57.
Bring next digit (2) of the dividend behind the 57 and repeat the process: 572 / 68

Moving on to step 4:
572 divided by 68 is 8 with a remainder of 28.
Record the quotient 8 as the next digit in the result. 
Result so far: 18.0
If we take 544 away from 572, we end up with 28.
Take the next digit (7) from the dividend and append it to 28, then repeat: 287 / 68

Step 5:
68 can be fit into 287 4 times, resulting in a remainder of 15.
Write down 4 as next digit of the result. 
Result so far: 184.0
Deduct 272 from 287 and we're left with 15.
Since there are no more digits in the dividend, we add a zero to the remainder making it 150, and continue the process.

Moving on to step 6:
When dividing 150 by 68, we get 2 with a remainder of 14.
The number 2 becomes the next digit in our result. 
Result so far: 184.2
If we take 136 away from 150, we end up with 14.
Since there are no more digits in the dividend, we add a zero to the remainder making it 140, and continue the process.

Advancing to step 7:
68 goes into 140 2 times with a remainder of 4.
Put 2 as the next digit of the answer. 
Result so far: 184.22
If we subtract 136 from 140, we get 4.
Since there are no more digits in the dividend, we add a zero to the remainder making it 40, and continue the process.

After the division, we end up with 184.22 and a remainder of 0.004.