We divide 46503 by 29
Let's see how many times 29 fits into 46503.

Step 1:
29 can be fit into 4 0 times, resulting in a remainder of 4.
The number 0 becomes the next digit in our result. 
Result so far: 0.0
Deduct 0 from 4 and we're left with 4.
Take the next digit (6) from the dividend and append it to 4, then repeat: 46 / 29

Moving on to step 2:
29 goes into 46 1 times with a remainder of 17.
The number 1 becomes the next digit in our result. 
Result so far: 1.0
If we subtract 29 from 46, we get 17.
Grab the next digit (5) from the dividend, add it to 17, then carry on: 175 / 29

Going ahead to step 3:
29 goes into 175 6 times with a remainder of 1.
Put 6 as the next digit of the answer. 
Result so far: 16.0
The remainder is 1 after subtracting 174 from 175.
Take the next digit (0) from the dividend and append it to 1, then repeat: 10 / 29

On to step 4:
10 divided by 29 is 0 with a remainder of 10.
Put 0 as the next digit of the answer. 
Result so far: 160.0
If we subtract 0 from 10, we get 10.
Fetch the next digit (3) from the dividend, attach it to 10 and continue: 103 / 29

Step 5:
If we divide 103 by 29, we get 3 and a remainder of 16.
The next digit of our result is 3. 
Result so far: 1603.0
Subtracting 87 from 103 leaves us with 16.
Since there are no more digits in the dividend, we add a zero to the remainder making it 160, and continue the process.

Moving on to step 6:
The number 29 fits into 160 5 times, leaving a remainder of 15.
Put 5 as the next digit of the answer. 
Result so far: 1603.5
The remainder is 15 after subtracting 145 from 160.
Since there are no more digits in the dividend, we add a zero to the remainder making it 150, and continue the process.

Advancing to step 7:
29 can be fit into 150 5 times, resulting in a remainder of 5.
Use 5 as the next digit of our solution. 
Result so far: 1603.55
If we subtract 145 from 150, we get 5.
Since there are no more digits in the dividend, we add a zero to the remainder making it 50, and continue the process.

The final outcome is 1603.55, with a leftover of 0.005.