105226 divided by 7 
Let's see how many times 7 fits into 105226.

Advancing to step 1:
The number 7 fits into 1 0 times, leaving a remainder of 1.
Use 0 as the next digit of our solution. 
Result so far: 0.0
If we take 0 away from 1, we end up with 1.
Grab the next digit (0) from the dividend, add it to 1, then carry on: 10 / 7

Advancing to step 2:
If we divide 10 by 7, we get 1 and a remainder of 3.
Put 1 as the next digit of the answer. 
Result so far: 1.0
If we take 7 away from 10, we end up with 3.
Fetch the next digit (5) from the dividend, attach it to 3 and continue: 35 / 7

Moving on to step 3:
7 goes into 35 5 times with a remainder of 0.
Put 5 as the next digit of the answer. 
Result so far: 15.0
Deduct 35 from 35 and we're left with 0.
Bring next digit (2) of the dividend behind the 0 and repeat the process: 2 / 7

Moving on to step 4:
7 can be fit into 2 0 times, resulting in a remainder of 2.
Use 0 as the next digit of our solution. 
Result so far: 150.0
Subtract 0 from 2 to get 2.
Bring next digit (2) of the dividend behind the 2 and repeat the process: 22 / 7

Advancing to step 5:
When dividing 22 by 7, we get 3 with a remainder of 1.
The number 3 becomes the next digit in our result. 
Result so far: 1503.0
If we subtract 21 from 22, we get 1.
Bring next digit (6) of the dividend behind the 1 and repeat the process: 16 / 7

On to step 6:
16 divided by 7 is 2 with a remainder of 2.
Use 2 as the next digit of our solution. 
Result so far: 15032.0
Subtract 14 from 16 to get 2.
Since there are no more digits in the dividend, we add a zero to the remainder making it 20, and continue the process.

Moving on to step 7:
7 can be fit into 20 2 times, resulting in a remainder of 6.
The number 2 becomes the next digit in our result. 
Result so far: 15032.2
Subtracting 14 from 20 leaves us with 6.
Since there are no more digits in the dividend, we add a zero to the remainder making it 60, and continue the process.

On to step 8:
The number 7 fits into 60 8 times, leaving a remainder of 4.
The number 8 becomes the next digit in our result. 
Result so far: 15032.28
Subtract 56 from 60 to get 4.
Since there are no more digits in the dividend, we add a zero to the remainder making it 40, and continue the process.

On to step 9:
40 divided by 7 is 5 with a remainder of 5.
Use 5 as the next digit of our solution. 
Result so far: 15032.285
Subtracting 35 from 40 leaves us with 5.
Since there are no more digits in the dividend, we add a zero to the remainder making it 50, and continue the process.

Step 10:
When dividing 50 by 7, we get 7 with a remainder of 1.
Write down 7 as next digit of the result. 
Result so far: 15032.2857
If we take 49 away from 50, we end up with 1.
Since there are no more digits in the dividend, we add a zero to the remainder making it 10, and continue the process.

Going ahead to step 11:
7 goes into 10 1 times with a remainder of 3.
Write down 1 as next digit of the result. 
Result so far: 15032.28571
Subtract 7 from 10 to get 3.
Since there are no more digits in the dividend, we add a zero to the remainder making it 30, and continue the process.

Advancing to step 12:
30 divided by 7 is 4 with a remainder of 2.
Put 4 as the next digit of the answer. 
Result so far: 15032.285714
The remainder is 2 after subtracting 28 from 30.
Since there are no more digits in the dividend, we add a zero to the remainder making it 20, and continue the process.

Advancing to step 13:
7 goes into 20 2 times with a remainder of 6.
The next digit of our result is 2. 
Result so far: 15032.2857142
The remainder is 6 after subtracting 14 from 20.
Since there are no more digits in the dividend, we add a zero to the remainder making it 60, and continue the process.

On to step 14:
If we divide 60 by 7, we get 8 and a remainder of 4.
The number 8 becomes the next digit in our result. 
Result so far: 15032.28571428
Subtracting 56 from 60 leaves us with 4.
Since there are no more digits in the dividend, we add a zero to the remainder making it 40, and continue the process.

Our division results in 15032.28571428 with a remaining 4e-09.