Let's divide 511935 by 7
Let's see how many times 7 fits into 511935.

Going ahead to step 1:
If we divide 5 by 7, we get 0 and a remainder of 5.
Write down 0 as next digit of the result. 
Result so far: 0.0
Deduct 0 from 5 and we're left with 5.
Include the next digit (1) from the dividend after 5, then repeat: 51 / 7

Going ahead to step 2:
51 divided by 7 is 7 with a remainder of 2.
Write down 7 as next digit of the result. 
Result so far: 7.0
The remainder is 2 after subtracting 49 from 51.
Take the next digit (1) from the dividend and append it to 2, then repeat: 21 / 7

Let's proceed to step 3:
7 goes into 21 3 times with a remainder of 0.
The number 3 becomes the next digit in our result. 
Result so far: 73.0
Subtract 21 from 21 to get 0.
Take the next digit (9) from the dividend and append it to 0, then repeat: 9 / 7

Moving on to step 4:
If we divide 9 by 7, we get 1 and a remainder of 2.
Put 1 as the next digit of the answer. 
Result so far: 731.0
The remainder is 2 after subtracting 7 from 9.
Grab the next digit (3) from the dividend, add it to 2, then carry on: 23 / 7

Step 5:
If we divide 23 by 7, we get 3 and a remainder of 2.
The next digit of our result is 3. 
Result so far: 7313.0
The remainder is 2 after subtracting 21 from 23.
Append the next digit (5) from the dividend to 2 and continue with: 25 / 7

On to step 6:
7 can be fit into 25 3 times, resulting in a remainder of 4.
Write down 3 as next digit of the result. 
Result so far: 73133.0
Subtracting 21 from 25 leaves us with 4.
Since there are no more digits in the dividend, we add a zero to the remainder making it 40, and continue the process.

Going ahead to step 7:
The number 7 fits into 40 5 times, leaving a remainder of 5.
Write down 5 as next digit of the result. 
Result so far: 73133.5
If we take 35 away from 40, we end up with 5.
Since there are no more digits in the dividend, we add a zero to the remainder making it 50, and continue the process.

Going ahead to step 8:
7 goes into 50 7 times with a remainder of 1.
Write down 7 as next digit of the result. 
Result so far: 73133.57
Subtract 49 from 50 to get 1.
Since there are no more digits in the dividend, we add a zero to the remainder making it 10, and continue the process.

On to step 9:
7 goes into 10 1 times with a remainder of 3.
The next digit of our result is 1. 
Result so far: 73133.571
The remainder is 3 after subtracting 7 from 10.
Since there are no more digits in the dividend, we add a zero to the remainder making it 30, and continue the process.

On to step 10:
The number 7 fits into 30 4 times, leaving a remainder of 2.
The next digit of our result is 4. 
Result so far: 73133.5714
Subtract 28 from 30 to get 2.
Since there are no more digits in the dividend, we add a zero to the remainder making it 20, and continue the process.

On to step 11:
20 divided by 7 is 2 with a remainder of 6.
Record the quotient 2 as the next digit in the result. 
Result so far: 73133.57142
The remainder is 6 after subtracting 14 from 20.
Since there are no more digits in the dividend, we add a zero to the remainder making it 60, and continue the process.

Step 12:
If we divide 60 by 7, we get 8 and a remainder of 4.
Put 8 as the next digit of the answer. 
Result so far: 73133.571428
If we take 56 away from 60, we end up with 4.
Since there are no more digits in the dividend, we add a zero to the remainder making it 40, and continue the process.

Let's proceed to step 13:
40 divided by 7 is 5 with a remainder of 5.
The number 5 becomes the next digit in our result. 
Result so far: 73133.5714285
The remainder is 5 after subtracting 35 from 40.
Since there are no more digits in the dividend, we add a zero to the remainder making it 50, and continue the process.

Moving on to step 14:
50 divided by 7 is 7 with a remainder of 1.
Put 7 as the next digit of the answer. 
Result so far: 73133.57142857
The remainder is 1 after subtracting 49 from 50.
Since there are no more digits in the dividend, we add a zero to the remainder making it 10, and continue the process.

The final outcome is 73133.57142857, with a leftover of 1e-09.