954417 ÷ 7 
Let's see how many times 7 fits into 954417.

Step 1:
9 divided by 7 is 1 with a remainder of 2.
Write down 1 as next digit of the result. 
Result so far: 1.0
Subtracting 7 from 9 leaves us with 2.
Include the next digit (5) from the dividend after 2, then repeat: 25 / 7

Going ahead to step 2:
25 divided by 7 is 3 with a remainder of 4.
The next digit of our result is 3. 
Result so far: 13.0
If we subtract 21 from 25, we get 4.
Include the next digit (4) from the dividend after 4, then repeat: 44 / 7

Going ahead to step 3:
When dividing 44 by 7, we get 6 with a remainder of 2.
The next digit of our result is 6. 
Result so far: 136.0
Subtract 42 from 44 to get 2.
Append the next digit (4) from the dividend to 2 and continue with: 24 / 7

Advancing to step 4:
If we divide 24 by 7, we get 3 and a remainder of 3.
Put 3 as the next digit of the answer. 
Result so far: 1363.0
If we take 21 away from 24, we end up with 3.
Append the next digit (1) from the dividend to 3 and continue with: 31 / 7

Advancing to step 5:
If we divide 31 by 7, we get 4 and a remainder of 3.
The next digit of our result is 4. 
Result so far: 13634.0
The remainder is 3 after subtracting 28 from 31.
Include the next digit (7) from the dividend after 3, then repeat: 37 / 7

On to step 6:
7 can be fit into 37 5 times, resulting in a remainder of 2.
Record the quotient 5 as the next digit in the result. 
Result so far: 136345.0
The remainder is 2 after subtracting 35 from 37.
Since there are no more digits in the dividend, we add a zero to the remainder making it 20, and continue the process.

Moving on to step 7:
7 goes into 20 2 times with a remainder of 6.
Put 2 as the next digit of the answer. 
Result so far: 136345.2
The remainder is 6 after subtracting 14 from 20.
Since there are no more digits in the dividend, we add a zero to the remainder making it 60, and continue the process.

Step 8:
If we divide 60 by 7, we get 8 and a remainder of 4.
Write down 8 as next digit of the result. 
Result so far: 136345.28
Subtract 56 from 60 to get 4.
Since there are no more digits in the dividend, we add a zero to the remainder making it 40, and continue the process.

Advancing to step 9:
The number 7 fits into 40 5 times, leaving a remainder of 5.
The next digit of our result is 5. 
Result so far: 136345.285
The remainder is 5 after subtracting 35 from 40.
Since there are no more digits in the dividend, we add a zero to the remainder making it 50, and continue the process.

Moving on to step 10:
7 can be fit into 50 7 times, resulting in a remainder of 1.
The number 7 becomes the next digit in our result. 
Result so far: 136345.2857
The remainder is 1 after subtracting 49 from 50.
Since there are no more digits in the dividend, we add a zero to the remainder making it 10, and continue the process.

Advancing to step 11:
The number 7 fits into 10 1 times, leaving a remainder of 3.
Put 1 as the next digit of the answer. 
Result so far: 136345.28571
Subtract 7 from 10 to get 3.
Since there are no more digits in the dividend, we add a zero to the remainder making it 30, and continue the process.

Moving on to step 12:
7 can be fit into 30 4 times, resulting in a remainder of 2.
The number 4 becomes the next digit in our result. 
Result so far: 136345.285714
Deduct 28 from 30 and we're left with 2.
Since there are no more digits in the dividend, we add a zero to the remainder making it 20, and continue the process.

Step 13:
If we divide 20 by 7, we get 2 and a remainder of 6.
Use 2 as the next digit of our solution. 
Result so far: 136345.2857142
Deduct 14 from 20 and we're left with 6.
Since there are no more digits in the dividend, we add a zero to the remainder making it 60, and continue the process.

Step 14:
When dividing 60 by 7, we get 8 with a remainder of 4.
Write down 8 as next digit of the result. 
Result so far: 136345.28571428
Deduct 56 from 60 and we're left with 4.
Since there are no more digits in the dividend, we add a zero to the remainder making it 40, and continue the process.

Our division results in 136345.28571428 with a remaining 4e-09.