Let's divide 50340 by 54
We're looking to find how many times 54 goes into 50340.

Let's proceed to step 1:
When dividing 5 by 54, we get 0 with a remainder of 5.
Write down 0 as next digit of the result. 
Result so far: 0.0
Deduct 0 from 5 and we're left with 5.
Grab the next digit (0) from the dividend, add it to 5, then carry on: 50 / 54

Step 2:
54 goes into 50 0 times with a remainder of 50.
Record the quotient 0 as the next digit in the result. 
Result so far: 0.0
If we take 0 away from 50, we end up with 50.
Grab the next digit (3) from the dividend, add it to 50, then carry on: 503 / 54

Advancing to step 3:
54 goes into 503 9 times with a remainder of 17.
Use 9 as the next digit of our solution. 
Result so far: 9.0
Deduct 486 from 503 and we're left with 17.
Fetch the next digit (4) from the dividend, attach it to 17 and continue: 174 / 54

Step 4:
54 goes into 174 3 times with a remainder of 12.
The number 3 becomes the next digit in our result. 
Result so far: 93.0
Subtract 162 from 174 to get 12.
Bring next digit (0) of the dividend behind the 12 and repeat the process: 120 / 54

Step 5:
54 can be fit into 120 2 times, resulting in a remainder of 12.
The next digit of our result is 2. 
Result so far: 932.0
If we subtract 108 from 120, we get 12.
Since there are no more digits in the dividend, we add a zero to the remainder making it 120, and continue the process.

Step 6:
120 divided by 54 is 2 with a remainder of 12.
Write down 2 as next digit of the result. 
Result so far: 932.2
Deduct 108 from 120 and we're left with 12.
Since there are no more digits in the dividend, we add a zero to the remainder making it 120, and continue the process.

Going ahead to step 7:
The number 54 fits into 120 2 times, leaving a remainder of 12.
The number 2 becomes the next digit in our result. 
Result so far: 932.22
If we subtract 108 from 120, we get 12.
Since there are no more digits in the dividend, we add a zero to the remainder making it 120, and continue the process.

The final outcome is 932.22, with a leftover of 0.012.