Let's divide 622890 by 7
The aim is to understand the frequency of 7 in 622890.

Step 1:
7 can be fit into 6 0 times, resulting in a remainder of 6.
Write down 0 as next digit of the result. 
Result so far: 0.0
Subtracting 0 from 6 leaves us with 6.
Include the next digit (2) from the dividend after 6, then repeat: 62 / 7

Step 2:
7 can be fit into 62 8 times, resulting in a remainder of 6.
Write down 8 as next digit of the result. 
Result so far: 8.0
Deduct 56 from 62 and we're left with 6.
Include the next digit (2) from the dividend after 6, then repeat: 62 / 7

Let's proceed to step 3:
62 divided by 7 is 8 with a remainder of 6.
Use 8 as the next digit of our solution. 
Result so far: 88.0
If we take 56 away from 62, we end up with 6.
Include the next digit (8) from the dividend after 6, then repeat: 68 / 7

Moving on to step 4:
When dividing 68 by 7, we get 9 with a remainder of 5.
Use 9 as the next digit of our solution. 
Result so far: 889.0
Subtract 63 from 68 to get 5.
Take the next digit (9) from the dividend and append it to 5, then repeat: 59 / 7

Moving on to step 5:
7 goes into 59 8 times with a remainder of 3.
Put 8 as the next digit of the answer. 
Result so far: 8898.0
Subtracting 56 from 59 leaves us with 3.
Grab the next digit (0) from the dividend, add it to 3, then carry on: 30 / 7

Moving on to step 6:
7 goes into 30 4 times with a remainder of 2.
Put 4 as the next digit of the answer. 
Result so far: 88984.0
If we take 28 away from 30, we end up with 2.
Since there are no more digits in the dividend, we add a zero to the remainder making it 20, and continue the process.

On to step 7:
The number 7 fits into 20 2 times, leaving a remainder of 6.
The next digit of our result is 2. 
Result so far: 88984.2
The remainder is 6 after subtracting 14 from 20.
Since there are no more digits in the dividend, we add a zero to the remainder making it 60, and continue the process.

Let's proceed to step 8:
7 goes into 60 8 times with a remainder of 4.
The number 8 becomes the next digit in our result. 
Result so far: 88984.28
Subtract 56 from 60 to get 4.
Since there are no more digits in the dividend, we add a zero to the remainder making it 40, and continue the process.

Let's proceed to step 9:
7 goes into 40 5 times with a remainder of 5.
Put 5 as the next digit of the answer. 
Result so far: 88984.285
The remainder is 5 after subtracting 35 from 40.
Since there are no more digits in the dividend, we add a zero to the remainder making it 50, and continue the process.

Advancing to step 10:
7 goes into 50 7 times with a remainder of 1.
The next digit of our result is 7. 
Result so far: 88984.2857
Deduct 49 from 50 and we're left with 1.
Since there are no more digits in the dividend, we add a zero to the remainder making it 10, and continue the process.

Going ahead to step 11:
7 can be fit into 10 1 times, resulting in a remainder of 3.
The next digit of our result is 1. 
Result so far: 88984.28571
Deduct 7 from 10 and we're left with 3.
Since there are no more digits in the dividend, we add a zero to the remainder making it 30, and continue the process.

Step 12:
When dividing 30 by 7, we get 4 with a remainder of 2.
Use 4 as the next digit of our solution. 
Result so far: 88984.285714
If we subtract 28 from 30, we get 2.
Since there are no more digits in the dividend, we add a zero to the remainder making it 20, and continue the process.

Going ahead to step 13:
20 divided by 7 is 2 with a remainder of 6.
Put 2 as the next digit of the answer. 
Result so far: 88984.2857142
If we take 14 away from 20, we end up with 6.
Since there are no more digits in the dividend, we add a zero to the remainder making it 60, and continue the process.

Advancing to step 14:
When dividing 60 by 7, we get 8 with a remainder of 4.
Use 8 as the next digit of our solution. 
Result so far: 88984.28571428
Deduct 56 from 60 and we're left with 4.
Since there are no more digits in the dividend, we add a zero to the remainder making it 40, and continue the process.

After the division, we end up with 88984.28571428 and a remainder of 4e-09.