88500 ÷ 50 
We want to figure out the number of times 88500 can be divided by 50.

Going ahead to step 1:
50 goes into 8 0 times with a remainder of 8.
Use 0 as the next digit of our solution. 
Result so far: 0.0
Deduct 0 from 8 and we're left with 8.
Append the next digit (8) from the dividend to 8 and continue with: 88 / 50

Step 2:
50 goes into 88 1 times with a remainder of 38.
Record the quotient 1 as the next digit in the result. 
Result so far: 1.0
Subtracting 50 from 88 leaves us with 38.
Grab the next digit (5) from the dividend, add it to 38, then carry on: 385 / 50

Step 3:
50 goes into 385 7 times with a remainder of 35.
The number 7 becomes the next digit in our result. 
Result so far: 17.0
Deduct 350 from 385 and we're left with 35.
Take the next digit (0) from the dividend and append it to 35, then repeat: 350 / 50

Advancing to step 4:
When dividing 350 by 50, we get 7 with a remainder of 0.
Record the quotient 7 as the next digit in the result. 
Result so far: 177.0
Subtract 350 from 350 to get 0.
Bring next digit (0) of the dividend behind the 0 and repeat the process: 0 / 50

Going ahead to step 5:
The number 50 fits into 0 0 times, leaving a remainder of 0.
Put 0 as the next digit of the answer. 
Result so far: 1770.0
Subtracting 0 from 0 leaves us with 0.
Since there are no more digits in the dividend, we add a zero to the remainder making it 0, and continue the process.

Going ahead to step 6:
When dividing 0 by 50, we get 0 with a remainder of 0.
Record the quotient 0 as the next digit in the result. 
Result so far: 1770.0
If we subtract 0 from 0, we get 0.
Since there are no more digits in the dividend, we add a zero to the remainder making it 0, and continue the process.

Step 7:
If we divide 0 by 50, we get 0 and a remainder of 0.
The next digit of our result is 0. 
Result so far: 1770.0
Subtract 0 from 0 to get 0.
Since there are no more digits in the dividend, we add a zero to the remainder making it 0, and continue the process.

After the division, we end up with 1770.0 and a remainder of 0.0.