295223 divided by 53 
Let's see how many times 53 fits into 295223.

Going ahead to step 1:
2 divided by 53 is 0 with a remainder of 2.
Write down 0 as next digit of the result. 
Result so far: 0.0
Subtracting 0 from 2 leaves us with 2.
Take the next digit (9) from the dividend and append it to 2, then repeat: 29 / 53

Advancing to step 2:
If we divide 29 by 53, we get 0 and a remainder of 29.
The number 0 becomes the next digit in our result. 
Result so far: 0.0
Subtracting 0 from 29 leaves us with 29.
Append the next digit (5) from the dividend to 29 and continue with: 295 / 53

Advancing to step 3:
If we divide 295 by 53, we get 5 and a remainder of 30.
The next digit of our result is 5. 
Result so far: 5.0
Subtract 265 from 295 to get 30.
Fetch the next digit (2) from the dividend, attach it to 30 and continue: 302 / 53

On to step 4:
The number 53 fits into 302 5 times, leaving a remainder of 37.
Use 5 as the next digit of our solution. 
Result so far: 55.0
Deduct 265 from 302 and we're left with 37.
Append the next digit (2) from the dividend to 37 and continue with: 372 / 53

Step 5:
When dividing 372 by 53, we get 7 with a remainder of 1.
The next digit of our result is 7. 
Result so far: 557.0
Subtract 371 from 372 to get 1.
Bring next digit (3) of the dividend behind the 1 and repeat the process: 13 / 53

Going ahead to step 6:
When dividing 13 by 53, we get 0 with a remainder of 13.
Use 0 as the next digit of our solution. 
Result so far: 5570.0
Deduct 0 from 13 and we're left with 13.
Since there are no more digits in the dividend, we add a zero to the remainder making it 130, and continue the process.

On to step 7:
53 can be fit into 130 2 times, resulting in a remainder of 24.
The number 2 becomes the next digit in our result. 
Result so far: 5570.2
If we subtract 106 from 130, we get 24.
Since there are no more digits in the dividend, we add a zero to the remainder making it 240, and continue the process.

Let's proceed to step 8:
53 can be fit into 240 4 times, resulting in a remainder of 28.
The next digit of our result is 4. 
Result so far: 5570.24
The remainder is 28 after subtracting 212 from 240.
Since there are no more digits in the dividend, we add a zero to the remainder making it 280, and continue the process.

Moving on to step 9:
If we divide 280 by 53, we get 5 and a remainder of 15.
The next digit of our result is 5. 
Result so far: 5570.245
If we subtract 265 from 280, we get 15.
Since there are no more digits in the dividend, we add a zero to the remainder making it 150, and continue the process.

Advancing to step 10:
The number 53 fits into 150 2 times, leaving a remainder of 44.
The next digit of our result is 2. 
Result so far: 5570.2452
Subtract 106 from 150 to get 44.
Since there are no more digits in the dividend, we add a zero to the remainder making it 440, and continue the process.

Step 11:
If we divide 440 by 53, we get 8 and a remainder of 16.
Use 8 as the next digit of our solution. 
Result so far: 5570.24528
Subtract 424 from 440 to get 16.
Since there are no more digits in the dividend, we add a zero to the remainder making it 160, and continue the process.

Step 12:
160 divided by 53 is 3 with a remainder of 1.
The number 3 becomes the next digit in our result. 
Result so far: 5570.245283
Subtract 159 from 160 to get 1.
Since there are no more digits in the dividend, we add a zero to the remainder making it 10, and continue the process.

Advancing to step 13:
When dividing 10 by 53, we get 0 with a remainder of 10.
The next digit of our result is 0. 
Result so far: 5570.245283
Deduct 0 from 10 and we're left with 10.
Since there are no more digits in the dividend, we add a zero to the remainder making it 100, and continue the process.

Step 14:
When dividing 100 by 53, we get 1 with a remainder of 47.
The next digit of our result is 1. 
Result so far: 5570.24528301
If we take 53 away from 100, we end up with 47.
Since there are no more digits in the dividend, we add a zero to the remainder making it 470, and continue the process.

The final outcome is 5570.24528301, with a leftover of 4.7e-08.