We're dividing 76676 by 3 
We want to divide 76676 by 3.

Going ahead to step 1:
3 can be fit into 7 2 times, resulting in a remainder of 1.
Write down 2 as next digit of the result. 
Result so far: 2.0
If we subtract 6 from 7, we get 1.
Include the next digit (6) from the dividend after 1, then repeat: 16 / 3

Going ahead to step 2:
If we divide 16 by 3, we get 5 and a remainder of 1.
The next digit of our result is 5. 
Result so far: 25.0
The remainder is 1 after subtracting 15 from 16.
Include the next digit (6) from the dividend after 1, then repeat: 16 / 3

On to step 3:
3 can be fit into 16 5 times, resulting in a remainder of 1.
Put 5 as the next digit of the answer. 
Result so far: 255.0
Subtract 15 from 16 to get 1.
Append the next digit (7) from the dividend to 1 and continue with: 17 / 3

Moving on to step 4:
3 can be fit into 17 5 times, resulting in a remainder of 2.
Write down 5 as next digit of the result. 
Result so far: 2555.0
If we take 15 away from 17, we end up with 2.
Include the next digit (6) from the dividend after 2, then repeat: 26 / 3

Let's proceed to step 5:
3 goes into 26 8 times with a remainder of 2.
The number 8 becomes the next digit in our result. 
Result so far: 25558.0
Subtracting 24 from 26 leaves us with 2.
Since there are no more digits in the dividend, we add a zero to the remainder making it 20, and continue the process.

Advancing to step 6:
3 can be fit into 20 6 times, resulting in a remainder of 2.
Put 6 as the next digit of the answer. 
Result so far: 25558.6
Deduct 18 from 20 and we're left with 2.
Since there are no more digits in the dividend, we add a zero to the remainder making it 20, and continue the process.

On to step 7:
3 goes into 20 6 times with a remainder of 2.
The number 6 becomes the next digit in our result. 
Result so far: 25558.66
Deduct 18 from 20 and we're left with 2.
Since there are no more digits in the dividend, we add a zero to the remainder making it 20, and continue the process.

In conclusion, the division gives 25558.66 with a balance of 0.002.