52640 divided by 15 
We want to figure out the number of times 52640 can be divided by 15.

Let's proceed to step 1:
When dividing 5 by 15, we get 0 with a remainder of 5.
Put 0 as the next digit of the answer. 
Result so far: 0.0
Deduct 0 from 5 and we're left with 5.
Grab the next digit (2) from the dividend, add it to 5, then carry on: 52 / 15

Step 2:
15 goes into 52 3 times with a remainder of 7.
Record the quotient 3 as the next digit in the result. 
Result so far: 3.0
Subtract 45 from 52 to get 7.
Take the next digit (6) from the dividend and append it to 7, then repeat: 76 / 15

On to step 3:
The number 15 fits into 76 5 times, leaving a remainder of 1.
Record the quotient 5 as the next digit in the result. 
Result so far: 35.0
Subtract 75 from 76 to get 1.
Append the next digit (4) from the dividend to 1 and continue with: 14 / 15

Going ahead to step 4:
The number 15 fits into 14 0 times, leaving a remainder of 14.
The number 0 becomes the next digit in our result. 
Result so far: 350.0
Deduct 0 from 14 and we're left with 14.
Append the next digit (0) from the dividend to 14 and continue with: 140 / 15

On to step 5:
The number 15 fits into 140 9 times, leaving a remainder of 5.
Write down 9 as next digit of the result. 
Result so far: 3509.0
Deduct 135 from 140 and we're left with 5.
Since there are no more digits in the dividend, we add a zero to the remainder making it 50, and continue the process.

Step 6:
50 divided by 15 is 3 with a remainder of 5.
Write down 3 as next digit of the result. 
Result so far: 3509.3
Subtracting 45 from 50 leaves us with 5.
Since there are no more digits in the dividend, we add a zero to the remainder making it 50, and continue the process.

Step 7:
15 can be fit into 50 3 times, resulting in a remainder of 5.
Record the quotient 3 as the next digit in the result. 
Result so far: 3509.33
Subtract 45 from 50 to get 5.
Since there are no more digits in the dividend, we add a zero to the remainder making it 50, and continue the process.

After the division, we end up with 3509.33 and a remainder of 0.005.