We're dividing 437392 by 7 
Let's see how many times 7 fits into 437392.

On to step 1:
The number 7 fits into 4 0 times, leaving a remainder of 4.
Write down 0 as next digit of the result. 
Result so far: 0.0
Subtracting 0 from 4 leaves us with 4.
Take the next digit (3) from the dividend and append it to 4, then repeat: 43 / 7

Going ahead to step 2:
If we divide 43 by 7, we get 6 and a remainder of 1.
The next digit of our result is 6. 
Result so far: 6.0
If we take 42 away from 43, we end up with 1.
Include the next digit (7) from the dividend after 1, then repeat: 17 / 7

Step 3:
When dividing 17 by 7, we get 2 with a remainder of 3.
The number 2 becomes the next digit in our result. 
Result so far: 62.0
The remainder is 3 after subtracting 14 from 17.
Grab the next digit (3) from the dividend, add it to 3, then carry on: 33 / 7

On to step 4:
7 can be fit into 33 4 times, resulting in a remainder of 5.
Use 4 as the next digit of our solution. 
Result so far: 624.0
If we take 28 away from 33, we end up with 5.
Include the next digit (9) from the dividend after 5, then repeat: 59 / 7

Step 5:
7 goes into 59 8 times with a remainder of 3.
The next digit of our result is 8. 
Result so far: 6248.0
The remainder is 3 after subtracting 56 from 59.
Grab the next digit (2) from the dividend, add it to 3, then carry on: 32 / 7

Step 6:
7 goes into 32 4 times with a remainder of 4.
The next digit of our result is 4. 
Result so far: 62484.0
Deduct 28 from 32 and we're left with 4.
Since there are no more digits in the dividend, we add a zero to the remainder making it 40, and continue the process.

Moving on to step 7:
When dividing 40 by 7, we get 5 with a remainder of 5.
Record the quotient 5 as the next digit in the result. 
Result so far: 62484.5
Subtract 35 from 40 to get 5.
Since there are no more digits in the dividend, we add a zero to the remainder making it 50, and continue the process.

On to step 8:
The number 7 fits into 50 7 times, leaving a remainder of 1.
Put 7 as the next digit of the answer. 
Result so far: 62484.57
Deduct 49 from 50 and we're left with 1.
Since there are no more digits in the dividend, we add a zero to the remainder making it 10, and continue the process.

Going ahead to step 9:
The number 7 fits into 10 1 times, leaving a remainder of 3.
Put 1 as the next digit of the answer. 
Result so far: 62484.571
If we subtract 7 from 10, we get 3.
Since there are no more digits in the dividend, we add a zero to the remainder making it 30, and continue the process.

Advancing to step 10:
The number 7 fits into 30 4 times, leaving a remainder of 2.
Write down 4 as next digit of the result. 
Result so far: 62484.5714
Subtracting 28 from 30 leaves us with 2.
Since there are no more digits in the dividend, we add a zero to the remainder making it 20, and continue the process.

Let's proceed to step 11:
When dividing 20 by 7, we get 2 with a remainder of 6.
The next digit of our result is 2. 
Result so far: 62484.57142
Deduct 14 from 20 and we're left with 6.
Since there are no more digits in the dividend, we add a zero to the remainder making it 60, and continue the process.

On to step 12:
If we divide 60 by 7, we get 8 and a remainder of 4.
The number 8 becomes the next digit in our result. 
Result so far: 62484.571428
If we subtract 56 from 60, we get 4.
Since there are no more digits in the dividend, we add a zero to the remainder making it 40, and continue the process.

Moving on to step 13:
40 divided by 7 is 5 with a remainder of 5.
The next digit of our result is 5. 
Result so far: 62484.5714285
Subtracting 35 from 40 leaves us with 5.
Since there are no more digits in the dividend, we add a zero to the remainder making it 50, and continue the process.

Going ahead to step 14:
7 can be fit into 50 7 times, resulting in a remainder of 1.
Put 7 as the next digit of the answer. 
Result so far: 62484.57142857
If we subtract 49 from 50, we get 1.
Since there are no more digits in the dividend, we add a zero to the remainder making it 10, and continue the process.

The final outcome is 62484.57142857, with a leftover of 1e-09.