63427079 ÷ 597 
We want to divide 63427079 by 597.

Advancing to step 1:
597 can be fit into 6 0 times, resulting in a remainder of 6.
The next digit of our result is 0. 
Result so far: 0.0
Deduct 0 from 6 and we're left with 6.
Include the next digit (3) from the dividend after 6, then repeat: 63 / 597

Going ahead to step 2:
63 divided by 597 is 0 with a remainder of 63.
Write down 0 as next digit of the result. 
Result so far: 0.0
The remainder is 63 after subtracting 0 from 63.
Append the next digit (4) from the dividend to 63 and continue with: 634 / 597

Advancing to step 3:
When dividing 634 by 597, we get 1 with a remainder of 37.
Use 1 as the next digit of our solution. 
Result so far: 1.0
If we subtract 597 from 634, we get 37.
Take the next digit (2) from the dividend and append it to 37, then repeat: 372 / 597

Advancing to step 4:
The number 597 fits into 372 0 times, leaving a remainder of 372.
The next digit of our result is 0. 
Result so far: 10.0
If we subtract 0 from 372, we get 372.
Append the next digit (7) from the dividend to 372 and continue with: 3727 / 597

Step 5:
The number 597 fits into 3727 6 times, leaving a remainder of 145.
Use 6 as the next digit of our solution. 
Result so far: 106.0
Subtracting 3582 from 3727 leaves us with 145.
Take the next digit (0) from the dividend and append it to 145, then repeat: 1450 / 597

Moving on to step 6:
597 goes into 1450 2 times with a remainder of 256.
Put 2 as the next digit of the answer. 
Result so far: 1062.0
Deduct 1194 from 1450 and we're left with 256.
Bring next digit (7) of the dividend behind the 256 and repeat the process: 2567 / 597

On to step 7:
597 goes into 2567 4 times with a remainder of 179.
Write down 4 as next digit of the result. 
Result so far: 10624.0
Subtract 2388 from 2567 to get 179.
Grab the next digit (9) from the dividend, add it to 179, then carry on: 1799 / 597

On to step 8:
When dividing 1799 by 597, we get 3 with a remainder of 8.
The next digit of our result is 3. 
Result so far: 106243.0
If we take 1791 away from 1799, we end up with 8.
Since there are no more digits in the dividend, we add a zero to the remainder making it 80, and continue the process.

Moving on to step 9:
The number 597 fits into 80 0 times, leaving a remainder of 80.
Put 0 as the next digit of the answer. 
Result so far: 106243.0
The remainder is 80 after subtracting 0 from 80.
Since there are no more digits in the dividend, we add a zero to the remainder making it 800, and continue the process.

Step 10:
When dividing 800 by 597, we get 1 with a remainder of 203.
The next digit of our result is 1. 
Result so far: 106243.01
The remainder is 203 after subtracting 597 from 800.
Since there are no more digits in the dividend, we add a zero to the remainder making it 2030, and continue the process.

Let's proceed to step 11:
597 goes into 2030 3 times with a remainder of 239.
Record the quotient 3 as the next digit in the result. 
Result so far: 106243.013
If we subtract 1791 from 2030, we get 239.
Since there are no more digits in the dividend, we add a zero to the remainder making it 2390, and continue the process.

Moving on to step 12:
2390 divided by 597 is 4 with a remainder of 2.
Write down 4 as next digit of the result. 
Result so far: 106243.0134
The remainder is 2 after subtracting 2388 from 2390.
Since there are no more digits in the dividend, we add a zero to the remainder making it 20, and continue the process.

Step 13:
If we divide 20 by 597, we get 0 and a remainder of 20.
Record the quotient 0 as the next digit in the result. 
Result so far: 106243.0134
Subtract 0 from 20 to get 20.
Since there are no more digits in the dividend, we add a zero to the remainder making it 200, and continue the process.

Going ahead to step 14:
597 goes into 200 0 times with a remainder of 200.
The next digit of our result is 0. 
Result so far: 106243.0134
Subtracting 0 from 200 leaves us with 200.
Since there are no more digits in the dividend, we add a zero to the remainder making it 2000, and continue the process.

The final result is 106243.0134 with a remainder of 2e-05.