Let's divide 161941 by 7
We're looking to find how many times 7 goes into 161941.

On to step 1:
When dividing 1 by 7, we get 0 with a remainder of 1.
The next digit of our result is 0. 
Result so far: 0.0
If we subtract 0 from 1, we get 1.
Include the next digit (6) from the dividend after 1, then repeat: 16 / 7

Let's proceed to step 2:
When dividing 16 by 7, we get 2 with a remainder of 2.
The number 2 becomes the next digit in our result. 
Result so far: 2.0
If we subtract 14 from 16, we get 2.
Take the next digit (1) from the dividend and append it to 2, then repeat: 21 / 7

Moving on to step 3:
If we divide 21 by 7, we get 3 and a remainder of 0.
The next digit of our result is 3. 
Result so far: 23.0
The remainder is 0 after subtracting 21 from 21.
Take the next digit (9) from the dividend and append it to 0, then repeat: 9 / 7

Step 4:
7 goes into 9 1 times with a remainder of 2.
Use 1 as the next digit of our solution. 
Result so far: 231.0
Deduct 7 from 9 and we're left with 2.
Grab the next digit (4) from the dividend, add it to 2, then carry on: 24 / 7

On to step 5:
24 divided by 7 is 3 with a remainder of 3.
The next digit of our result is 3. 
Result so far: 2313.0
If we subtract 21 from 24, we get 3.
Fetch the next digit (1) from the dividend, attach it to 3 and continue: 31 / 7

Step 6:
If we divide 31 by 7, we get 4 and a remainder of 3.
Put 4 as the next digit of the answer. 
Result so far: 23134.0
If we take 28 away from 31, we end up with 3.
Since there are no more digits in the dividend, we add a zero to the remainder making it 30, and continue the process.

On to step 7:
7 can be fit into 30 4 times, resulting in a remainder of 2.
The number 4 becomes the next digit in our result. 
Result so far: 23134.4
Subtracting 28 from 30 leaves us with 2.
Since there are no more digits in the dividend, we add a zero to the remainder making it 20, and continue the process.

Advancing to step 8:
When dividing 20 by 7, we get 2 with a remainder of 6.
The number 2 becomes the next digit in our result. 
Result so far: 23134.42
Subtract 14 from 20 to get 6.
Since there are no more digits in the dividend, we add a zero to the remainder making it 60, and continue the process.

Moving on to step 9:
When dividing 60 by 7, we get 8 with a remainder of 4.
Write down 8 as next digit of the result. 
Result so far: 23134.428
Subtract 56 from 60 to get 4.
Since there are no more digits in the dividend, we add a zero to the remainder making it 40, and continue the process.

Going ahead to step 10:
40 divided by 7 is 5 with a remainder of 5.
The next digit of our result is 5. 
Result so far: 23134.4285
If we take 35 away from 40, we end up with 5.
Since there are no more digits in the dividend, we add a zero to the remainder making it 50, and continue the process.

Going ahead to step 11:
If we divide 50 by 7, we get 7 and a remainder of 1.
Record the quotient 7 as the next digit in the result. 
Result so far: 23134.42857
Subtracting 49 from 50 leaves us with 1.
Since there are no more digits in the dividend, we add a zero to the remainder making it 10, and continue the process.

On to step 12:
If we divide 10 by 7, we get 1 and a remainder of 3.
The number 1 becomes the next digit in our result. 
Result so far: 23134.428571
Subtract 7 from 10 to get 3.
Since there are no more digits in the dividend, we add a zero to the remainder making it 30, and continue the process.

Going ahead to step 13:
7 can be fit into 30 4 times, resulting in a remainder of 2.
Use 4 as the next digit of our solution. 
Result so far: 23134.4285714
Subtract 28 from 30 to get 2.
Since there are no more digits in the dividend, we add a zero to the remainder making it 20, and continue the process.

Moving on to step 14:
7 can be fit into 20 2 times, resulting in a remainder of 6.
The next digit of our result is 2. 
Result so far: 23134.42857142
Subtract 14 from 20 to get 6.
Since there are no more digits in the dividend, we add a zero to the remainder making it 60, and continue the process.

The quotient of the division is 23134.42857142, and the remainder is 6e-09.