97684097 ÷ 85 
We want to divide 97684097 by 85.

Let's proceed to step 1:
9 divided by 85 is 0 with a remainder of 9.
Put 0 as the next digit of the answer. 
Result so far: 0.0
If we take 0 away from 9, we end up with 9.
Grab the next digit (7) from the dividend, add it to 9, then carry on: 97 / 85

On to step 2:
97 divided by 85 is 1 with a remainder of 12.
Use 1 as the next digit of our solution. 
Result so far: 1.0
If we take 85 away from 97, we end up with 12.
Append the next digit (6) from the dividend to 12 and continue with: 126 / 85

Step 3:
85 can be fit into 126 1 times, resulting in a remainder of 41.
Write down 1 as next digit of the result. 
Result so far: 11.0
If we subtract 85 from 126, we get 41.
Append the next digit (8) from the dividend to 41 and continue with: 418 / 85

On to step 4:
The number 85 fits into 418 4 times, leaving a remainder of 78.
Put 4 as the next digit of the answer. 
Result so far: 114.0
The remainder is 78 after subtracting 340 from 418.
Grab the next digit (4) from the dividend, add it to 78, then carry on: 784 / 85

Moving on to step 5:
85 goes into 784 9 times with a remainder of 19.
The number 9 becomes the next digit in our result. 
Result so far: 1149.0
Subtract 765 from 784 to get 19.
Fetch the next digit (0) from the dividend, attach it to 19 and continue: 190 / 85

Advancing to step 6:
85 can be fit into 190 2 times, resulting in a remainder of 20.
The next digit of our result is 2. 
Result so far: 11492.0
If we subtract 170 from 190, we get 20.
Bring next digit (9) of the dividend behind the 20 and repeat the process: 209 / 85

Let's proceed to step 7:
When dividing 209 by 85, we get 2 with a remainder of 39.
The next digit of our result is 2. 
Result so far: 114922.0
Subtracting 170 from 209 leaves us with 39.
Grab the next digit (7) from the dividend, add it to 39, then carry on: 397 / 85

Moving on to step 8:
If we divide 397 by 85, we get 4 and a remainder of 57.
Put 4 as the next digit of the answer. 
Result so far: 1149224.0
Subtract 340 from 397 to get 57.
Since there are no more digits in the dividend, we add a zero to the remainder making it 570, and continue the process.

Moving on to step 9:
The number 85 fits into 570 6 times, leaving a remainder of 60.
Record the quotient 6 as the next digit in the result. 
Result so far: 1149224.6
If we subtract 510 from 570, we get 60.
Since there are no more digits in the dividend, we add a zero to the remainder making it 600, and continue the process.

Let's proceed to step 10:
85 goes into 600 7 times with a remainder of 5.
The next digit of our result is 7. 
Result so far: 1149224.67
Subtracting 595 from 600 leaves us with 5.
Since there are no more digits in the dividend, we add a zero to the remainder making it 50, and continue the process.

On to step 11:
85 goes into 50 0 times with a remainder of 50.
Use 0 as the next digit of our solution. 
Result so far: 1149224.67
The remainder is 50 after subtracting 0 from 50.
Since there are no more digits in the dividend, we add a zero to the remainder making it 500, and continue the process.

Let's proceed to step 12:
The number 85 fits into 500 5 times, leaving a remainder of 75.
Put 5 as the next digit of the answer. 
Result so far: 1149224.6705
Deduct 425 from 500 and we're left with 75.
Since there are no more digits in the dividend, we add a zero to the remainder making it 750, and continue the process.

Going ahead to step 13:
85 can be fit into 750 8 times, resulting in a remainder of 70.
Put 8 as the next digit of the answer. 
Result so far: 1149224.67058
Subtract 680 from 750 to get 70.
Since there are no more digits in the dividend, we add a zero to the remainder making it 700, and continue the process.

On to step 14:
If we divide 700 by 85, we get 8 and a remainder of 20.
Record the quotient 8 as the next digit in the result. 
Result so far: 1149224.670588
Subtracting 680 from 700 leaves us with 20.
Since there are no more digits in the dividend, we add a zero to the remainder making it 200, and continue the process.

The final outcome is 1149224.670588, with a leftover of 2e-06.