59990 ÷ 3 
Our goal is to divide 59990 by 3.

Advancing to step 1:
The number 3 fits into 5 1 times, leaving a remainder of 2.
The next digit of our result is 1. 
Result so far: 1.0
Subtracting 3 from 5 leaves us with 2.
Append the next digit (9) from the dividend to 2 and continue with: 29 / 3

Going ahead to step 2:
If we divide 29 by 3, we get 9 and a remainder of 2.
Put 9 as the next digit of the answer. 
Result so far: 19.0
Subtracting 27 from 29 leaves us with 2.
Fetch the next digit (9) from the dividend, attach it to 2 and continue: 29 / 3

Let's proceed to step 3:
If we divide 29 by 3, we get 9 and a remainder of 2.
The number 9 becomes the next digit in our result. 
Result so far: 199.0
If we take 27 away from 29, we end up with 2.
Fetch the next digit (9) from the dividend, attach it to 2 and continue: 29 / 3

Advancing to step 4:
3 goes into 29 9 times with a remainder of 2.
Use 9 as the next digit of our solution. 
Result so far: 1999.0
If we subtract 27 from 29, we get 2.
Bring next digit (0) of the dividend behind the 2 and repeat the process: 20 / 3

Step 5:
3 can be fit into 20 6 times, resulting in a remainder of 2.
The number 6 becomes the next digit in our result. 
Result so far: 19996.0
If we take 18 away from 20, we end up with 2.
Since there are no more digits in the dividend, we add a zero to the remainder making it 20, and continue the process.

Going ahead to step 6:
When dividing 20 by 3, we get 6 with a remainder of 2.
Record the quotient 6 as the next digit in the result. 
Result so far: 19996.6
If we take 18 away from 20, we end up with 2.
Since there are no more digits in the dividend, we add a zero to the remainder making it 20, and continue the process.

Let's proceed to step 7:
3 goes into 20 6 times with a remainder of 2.
The next digit of our result is 6. 
Result so far: 19996.66
If we subtract 18 from 20, we get 2.
Since there are no more digits in the dividend, we add a zero to the remainder making it 20, and continue the process.

The quotient of the division is 19996.66, and the remainder is 0.002.