Let's divide 528104 by 33
Let's see how many times 33 fits into 528104.

Going ahead to step 1:
5 divided by 33 is 0 with a remainder of 5.
The next digit of our result is 0. 
Result so far: 0.0
Subtracting 0 from 5 leaves us with 5.
Include the next digit (2) from the dividend after 5, then repeat: 52 / 33

Going ahead to step 2:
33 can be fit into 52 1 times, resulting in a remainder of 19.
Put 1 as the next digit of the answer. 
Result so far: 1.0
Deduct 33 from 52 and we're left with 19.
Bring next digit (8) of the dividend behind the 19 and repeat the process: 198 / 33

Moving on to step 3:
If we divide 198 by 33, we get 6 and a remainder of 0.
The next digit of our result is 6. 
Result so far: 16.0
The remainder is 0 after subtracting 198 from 198.
Append the next digit (1) from the dividend to 0 and continue with: 1 / 33

Going ahead to step 4:
33 goes into 1 0 times with a remainder of 1.
Write down 0 as next digit of the result. 
Result so far: 160.0
Deduct 0 from 1 and we're left with 1.
Fetch the next digit (0) from the dividend, attach it to 1 and continue: 10 / 33

Let's proceed to step 5:
If we divide 10 by 33, we get 0 and a remainder of 10.
Use 0 as the next digit of our solution. 
Result so far: 1600.0
If we subtract 0 from 10, we get 10.
Fetch the next digit (4) from the dividend, attach it to 10 and continue: 104 / 33

Step 6:
104 divided by 33 is 3 with a remainder of 5.
The number 3 becomes the next digit in our result. 
Result so far: 16003.0
Deduct 99 from 104 and we're left with 5.
Since there are no more digits in the dividend, we add a zero to the remainder making it 50, and continue the process.

Moving on to step 7:
When dividing 50 by 33, we get 1 with a remainder of 17.
The number 1 becomes the next digit in our result. 
Result so far: 16003.1
Subtract 33 from 50 to get 17.
Since there are no more digits in the dividend, we add a zero to the remainder making it 170, and continue the process.

Step 8:
170 divided by 33 is 5 with a remainder of 5.
Write down 5 as next digit of the result. 
Result so far: 16003.15
Subtract 165 from 170 to get 5.
Since there are no more digits in the dividend, we add a zero to the remainder making it 50, and continue the process.

On to step 9:
The number 33 fits into 50 1 times, leaving a remainder of 17.
Put 1 as the next digit of the answer. 
Result so far: 16003.151
Subtract 33 from 50 to get 17.
Since there are no more digits in the dividend, we add a zero to the remainder making it 170, and continue the process.

Going ahead to step 10:
If we divide 170 by 33, we get 5 and a remainder of 5.
Put 5 as the next digit of the answer. 
Result so far: 16003.1515
The remainder is 5 after subtracting 165 from 170.
Since there are no more digits in the dividend, we add a zero to the remainder making it 50, and continue the process.

On to step 11:
33 can be fit into 50 1 times, resulting in a remainder of 17.
Record the quotient 1 as the next digit in the result. 
Result so far: 16003.15151
If we subtract 33 from 50, we get 17.
Since there are no more digits in the dividend, we add a zero to the remainder making it 170, and continue the process.

Going ahead to step 12:
33 can be fit into 170 5 times, resulting in a remainder of 5.
The number 5 becomes the next digit in our result. 
Result so far: 16003.151515
Subtract 165 from 170 to get 5.
Since there are no more digits in the dividend, we add a zero to the remainder making it 50, and continue the process.

Step 13:
50 divided by 33 is 1 with a remainder of 17.
Put 1 as the next digit of the answer. 
Result so far: 16003.1515151
Subtract 33 from 50 to get 17.
Since there are no more digits in the dividend, we add a zero to the remainder making it 170, and continue the process.

On to step 14:
33 can be fit into 170 5 times, resulting in a remainder of 5.
Write down 5 as next digit of the result. 
Result so far: 16003.15151515
Deduct 165 from 170 and we're left with 5.
Since there are no more digits in the dividend, we add a zero to the remainder making it 50, and continue the process.

After the division, we end up with 16003.15151515 and a remainder of 5e-09.