We look at the division of 577873 by 7 
We're looking to find how many times 7 goes into 577873.

Going ahead to step 1:
7 goes into 5 0 times with a remainder of 5.
The next digit of our result is 0. 
Result so far: 0.0
If we subtract 0 from 5, we get 5.
Fetch the next digit (7) from the dividend, attach it to 5 and continue: 57 / 7

Step 2:
7 can be fit into 57 8 times, resulting in a remainder of 1.
Record the quotient 8 as the next digit in the result. 
Result so far: 8.0
Subtracting 56 from 57 leaves us with 1.
Append the next digit (7) from the dividend to 1 and continue with: 17 / 7

Going ahead to step 3:
17 divided by 7 is 2 with a remainder of 3.
Write down 2 as next digit of the result. 
Result so far: 82.0
Deduct 14 from 17 and we're left with 3.
Include the next digit (8) from the dividend after 3, then repeat: 38 / 7

On to step 4:
The number 7 fits into 38 5 times, leaving a remainder of 3.
Record the quotient 5 as the next digit in the result. 
Result so far: 825.0
Subtracting 35 from 38 leaves us with 3.
Append the next digit (7) from the dividend to 3 and continue with: 37 / 7

Step 5:
The number 7 fits into 37 5 times, leaving a remainder of 2.
Write down 5 as next digit of the result. 
Result so far: 8255.0
Subtract 35 from 37 to get 2.
Bring next digit (3) of the dividend behind the 2 and repeat the process: 23 / 7

Going ahead to step 6:
If we divide 23 by 7, we get 3 and a remainder of 2.
The next digit of our result is 3. 
Result so far: 82553.0
Subtracting 21 from 23 leaves us with 2.
Since there are no more digits in the dividend, we add a zero to the remainder making it 20, and continue the process.

Going ahead to step 7:
When dividing 20 by 7, we get 2 with a remainder of 6.
Write down 2 as next digit of the result. 
Result so far: 82553.2
If we subtract 14 from 20, we get 6.
Since there are no more digits in the dividend, we add a zero to the remainder making it 60, and continue the process.

Advancing to step 8:
When dividing 60 by 7, we get 8 with a remainder of 4.
Put 8 as the next digit of the answer. 
Result so far: 82553.28
Subtract 56 from 60 to get 4.
Since there are no more digits in the dividend, we add a zero to the remainder making it 40, and continue the process.

Going ahead to step 9:
7 can be fit into 40 5 times, resulting in a remainder of 5.
The number 5 becomes the next digit in our result. 
Result so far: 82553.285
Subtract 35 from 40 to get 5.
Since there are no more digits in the dividend, we add a zero to the remainder making it 50, and continue the process.

Step 10:
When dividing 50 by 7, we get 7 with a remainder of 1.
Use 7 as the next digit of our solution. 
Result so far: 82553.2857
Subtracting 49 from 50 leaves us with 1.
Since there are no more digits in the dividend, we add a zero to the remainder making it 10, and continue the process.

Step 11:
7 goes into 10 1 times with a remainder of 3.
The next digit of our result is 1. 
Result so far: 82553.28571
Subtract 7 from 10 to get 3.
Since there are no more digits in the dividend, we add a zero to the remainder making it 30, and continue the process.

On to step 12:
7 can be fit into 30 4 times, resulting in a remainder of 2.
Put 4 as the next digit of the answer. 
Result so far: 82553.285714
If we subtract 28 from 30, we get 2.
Since there are no more digits in the dividend, we add a zero to the remainder making it 20, and continue the process.

Moving on to step 13:
20 divided by 7 is 2 with a remainder of 6.
Put 2 as the next digit of the answer. 
Result so far: 82553.2857142
The remainder is 6 after subtracting 14 from 20.
Since there are no more digits in the dividend, we add a zero to the remainder making it 60, and continue the process.

Advancing to step 14:
If we divide 60 by 7, we get 8 and a remainder of 4.
The number 8 becomes the next digit in our result. 
Result so far: 82553.28571428
If we take 56 away from 60, we end up with 4.
Since there are no more digits in the dividend, we add a zero to the remainder making it 40, and continue the process.

After the division, we end up with 82553.28571428 and a remainder of 4e-09.