766884 ÷ 17 
We want to divide 766884 by 17.

Advancing to step 1:
7 divided by 17 is 0 with a remainder of 7.
The next digit of our result is 0. 
Result so far: 0.0
Subtracting 0 from 7 leaves us with 7.
Include the next digit (6) from the dividend after 7, then repeat: 76 / 17

Going ahead to step 2:
17 can be fit into 76 4 times, resulting in a remainder of 8.
The number 4 becomes the next digit in our result. 
Result so far: 4.0
Subtracting 68 from 76 leaves us with 8.
Fetch the next digit (6) from the dividend, attach it to 8 and continue: 86 / 17

On to step 3:
When dividing 86 by 17, we get 5 with a remainder of 1.
Write down 5 as next digit of the result. 
Result so far: 45.0
The remainder is 1 after subtracting 85 from 86.
Bring next digit (8) of the dividend behind the 1 and repeat the process: 18 / 17

Going ahead to step 4:
The number 17 fits into 18 1 times, leaving a remainder of 1.
Put 1 as the next digit of the answer. 
Result so far: 451.0
Deduct 17 from 18 and we're left with 1.
Take the next digit (8) from the dividend and append it to 1, then repeat: 18 / 17

Let's proceed to step 5:
17 goes into 18 1 times with a remainder of 1.
The next digit of our result is 1. 
Result so far: 4511.0
Subtract 17 from 18 to get 1.
Bring next digit (4) of the dividend behind the 1 and repeat the process: 14 / 17

Going ahead to step 6:
If we divide 14 by 17, we get 0 and a remainder of 14.
Write down 0 as next digit of the result. 
Result so far: 45110.0
If we subtract 0 from 14, we get 14.
Since there are no more digits in the dividend, we add a zero to the remainder making it 140, and continue the process.

Advancing to step 7:
140 divided by 17 is 8 with a remainder of 4.
The next digit of our result is 8. 
Result so far: 45110.8
If we take 136 away from 140, we end up with 4.
Since there are no more digits in the dividend, we add a zero to the remainder making it 40, and continue the process.

Let's proceed to step 8:
17 can be fit into 40 2 times, resulting in a remainder of 6.
Use 2 as the next digit of our solution. 
Result so far: 45110.82
Deduct 34 from 40 and we're left with 6.
Since there are no more digits in the dividend, we add a zero to the remainder making it 60, and continue the process.

On to step 9:
The number 17 fits into 60 3 times, leaving a remainder of 9.
Write down 3 as next digit of the result. 
Result so far: 45110.823
Subtract 51 from 60 to get 9.
Since there are no more digits in the dividend, we add a zero to the remainder making it 90, and continue the process.

On to step 10:
90 divided by 17 is 5 with a remainder of 5.
Use 5 as the next digit of our solution. 
Result so far: 45110.8235
The remainder is 5 after subtracting 85 from 90.
Since there are no more digits in the dividend, we add a zero to the remainder making it 50, and continue the process.

Step 11:
50 divided by 17 is 2 with a remainder of 16.
Put 2 as the next digit of the answer. 
Result so far: 45110.82352
Deduct 34 from 50 and we're left with 16.
Since there are no more digits in the dividend, we add a zero to the remainder making it 160, and continue the process.

Going ahead to step 12:
If we divide 160 by 17, we get 9 and a remainder of 7.
The next digit of our result is 9. 
Result so far: 45110.823529
Subtracting 153 from 160 leaves us with 7.
Since there are no more digits in the dividend, we add a zero to the remainder making it 70, and continue the process.

Advancing to step 13:
70 divided by 17 is 4 with a remainder of 2.
Use 4 as the next digit of our solution. 
Result so far: 45110.8235294
The remainder is 2 after subtracting 68 from 70.
Since there are no more digits in the dividend, we add a zero to the remainder making it 20, and continue the process.

Step 14:
20 divided by 17 is 1 with a remainder of 3.
Put 1 as the next digit of the answer. 
Result so far: 45110.82352941
The remainder is 3 after subtracting 17 from 20.
Since there are no more digits in the dividend, we add a zero to the remainder making it 30, and continue the process.

In conclusion, the division gives 45110.82352941 with a balance of 3e-09.