We look at the division of 5295 by 33 
We're looking to find how many times 33 goes into 5295.

Advancing to step 1:
When dividing 5 by 33, we get 0 with a remainder of 5.
The number 0 becomes the next digit in our result. 
Result so far: 0.0
Deduct 0 from 5 and we're left with 5.
Grab the next digit (2) from the dividend, add it to 5, then carry on: 52 / 33

Moving on to step 2:
The number 33 fits into 52 1 times, leaving a remainder of 19.
Record the quotient 1 as the next digit in the result. 
Result so far: 1.0
The remainder is 19 after subtracting 33 from 52.
Include the next digit (9) from the dividend after 19, then repeat: 199 / 33

Moving on to step 3:
199 divided by 33 is 6 with a remainder of 1.
Put 6 as the next digit of the answer. 
Result so far: 16.0
Subtract 198 from 199 to get 1.
Take the next digit (5) from the dividend and append it to 1, then repeat: 15 / 33

Going ahead to step 4:
When dividing 15 by 33, we get 0 with a remainder of 15.
Record the quotient 0 as the next digit in the result. 
Result so far: 160.0
If we take 0 away from 15, we end up with 15.
Since there are no more digits in the dividend, we add a zero to the remainder making it 150, and continue the process.

Moving on to step 5:
33 can be fit into 150 4 times, resulting in a remainder of 18.
Write down 4 as next digit of the result. 
Result so far: 160.4
If we take 132 away from 150, we end up with 18.
Since there are no more digits in the dividend, we add a zero to the remainder making it 180, and continue the process.

On to step 6:
When dividing 180 by 33, we get 5 with a remainder of 15.
Use 5 as the next digit of our solution. 
Result so far: 160.45
The remainder is 15 after subtracting 165 from 180.
Since there are no more digits in the dividend, we add a zero to the remainder making it 150, and continue the process.

On to step 7:
150 divided by 33 is 4 with a remainder of 18.
Record the quotient 4 as the next digit in the result. 
Result so far: 160.454
Subtracting 132 from 150 leaves us with 18.
Since there are no more digits in the dividend, we add a zero to the remainder making it 180, and continue the process.

Let's proceed to step 8:
When dividing 180 by 33, we get 5 with a remainder of 15.
Record the quotient 5 as the next digit in the result. 
Result so far: 160.4545
Subtracting 165 from 180 leaves us with 15.
Since there are no more digits in the dividend, we add a zero to the remainder making it 150, and continue the process.

Going ahead to step 9:
When dividing 150 by 33, we get 4 with a remainder of 18.
Use 4 as the next digit of our solution. 
Result so far: 160.45454
Subtract 132 from 150 to get 18.
Since there are no more digits in the dividend, we add a zero to the remainder making it 180, and continue the process.

Step 10:
The number 33 fits into 180 5 times, leaving a remainder of 15.
The number 5 becomes the next digit in our result. 
Result so far: 160.454545
Subtract 165 from 180 to get 15.
Since there are no more digits in the dividend, we add a zero to the remainder making it 150, and continue the process.

Moving on to step 11:
33 can be fit into 150 4 times, resulting in a remainder of 18.
The number 4 becomes the next digit in our result. 
Result so far: 160.4545454
Subtract 132 from 150 to get 18.
Since there are no more digits in the dividend, we add a zero to the remainder making it 180, and continue the process.

Step 12:
33 goes into 180 5 times with a remainder of 15.
The number 5 becomes the next digit in our result. 
Result so far: 160.45454545
If we subtract 165 from 180, we get 15.
Since there are no more digits in the dividend, we add a zero to the remainder making it 150, and continue the process.

The final outcome is 160.45454545, with a leftover of 1.5e-08.