394407 ÷ 58 
Let's see how many times 58 fits into 394407.

Step 1:
3 divided by 58 is 0 with a remainder of 3.
Write down 0 as next digit of the result. 
Result so far: 0.0
Deduct 0 from 3 and we're left with 3.
Take the next digit (9) from the dividend and append it to 3, then repeat: 39 / 58

Advancing to step 2:
When dividing 39 by 58, we get 0 with a remainder of 39.
Use 0 as the next digit of our solution. 
Result so far: 0.0
Subtract 0 from 39 to get 39.
Take the next digit (4) from the dividend and append it to 39, then repeat: 394 / 58

Advancing to step 3:
394 divided by 58 is 6 with a remainder of 46.
The number 6 becomes the next digit in our result. 
Result so far: 6.0
If we take 348 away from 394, we end up with 46.
Include the next digit (4) from the dividend after 46, then repeat: 464 / 58

Going ahead to step 4:
When dividing 464 by 58, we get 8 with a remainder of 0.
Record the quotient 8 as the next digit in the result. 
Result so far: 68.0
If we subtract 464 from 464, we get 0.
Include the next digit (0) from the dividend after 0, then repeat: 0 / 58

Let's proceed to step 5:
If we divide 0 by 58, we get 0 and a remainder of 0.
The next digit of our result is 0. 
Result so far: 680.0
If we take 0 away from 0, we end up with 0.
Grab the next digit (7) from the dividend, add it to 0, then carry on: 7 / 58

Going ahead to step 6:
The number 58 fits into 7 0 times, leaving a remainder of 7.
The next digit of our result is 0. 
Result so far: 6800.0
Deduct 0 from 7 and we're left with 7.
Since there are no more digits in the dividend, we add a zero to the remainder making it 70, and continue the process.

On to step 7:
When dividing 70 by 58, we get 1 with a remainder of 12.
Put 1 as the next digit of the answer. 
Result so far: 6800.1
If we subtract 58 from 70, we get 12.
Since there are no more digits in the dividend, we add a zero to the remainder making it 120, and continue the process.

On to step 8:
120 divided by 58 is 2 with a remainder of 4.
Put 2 as the next digit of the answer. 
Result so far: 6800.12
Subtracting 116 from 120 leaves us with 4.
Since there are no more digits in the dividend, we add a zero to the remainder making it 40, and continue the process.

On to step 9:
58 goes into 40 0 times with a remainder of 40.
The number 0 becomes the next digit in our result. 
Result so far: 6800.12
The remainder is 40 after subtracting 0 from 40.
Since there are no more digits in the dividend, we add a zero to the remainder making it 400, and continue the process.

Going ahead to step 10:
400 divided by 58 is 6 with a remainder of 52.
The number 6 becomes the next digit in our result. 
Result so far: 6800.1206
The remainder is 52 after subtracting 348 from 400.
Since there are no more digits in the dividend, we add a zero to the remainder making it 520, and continue the process.

Step 11:
If we divide 520 by 58, we get 8 and a remainder of 56.
The number 8 becomes the next digit in our result. 
Result so far: 6800.12068
If we subtract 464 from 520, we get 56.
Since there are no more digits in the dividend, we add a zero to the remainder making it 560, and continue the process.

Going ahead to step 12:
58 goes into 560 9 times with a remainder of 38.
Put 9 as the next digit of the answer. 
Result so far: 6800.120689
Subtract 522 from 560 to get 38.
Since there are no more digits in the dividend, we add a zero to the remainder making it 380, and continue the process.

On to step 13:
When dividing 380 by 58, we get 6 with a remainder of 32.
Use 6 as the next digit of our solution. 
Result so far: 6800.1206896
Subtract 348 from 380 to get 32.
Since there are no more digits in the dividend, we add a zero to the remainder making it 320, and continue the process.

Moving on to step 14:
58 goes into 320 5 times with a remainder of 30.
Put 5 as the next digit of the answer. 
Result so far: 6800.12068965
If we take 290 away from 320, we end up with 30.
Since there are no more digits in the dividend, we add a zero to the remainder making it 300, and continue the process.

The final outcome is 6800.12068965, with a leftover of 3e-08.