669150 divided by 7 
Let's see how many times 7 fits into 669150.

On to step 1:
7 can be fit into 6 0 times, resulting in a remainder of 6.
The next digit of our result is 0. 
Result so far: 0.0
Subtract 0 from 6 to get 6.
Append the next digit (6) from the dividend to 6 and continue with: 66 / 7

Advancing to step 2:
7 goes into 66 9 times with a remainder of 3.
Record the quotient 9 as the next digit in the result. 
Result so far: 9.0
Subtract 63 from 66 to get 3.
Append the next digit (9) from the dividend to 3 and continue with: 39 / 7

On to step 3:
39 divided by 7 is 5 with a remainder of 4.
Use 5 as the next digit of our solution. 
Result so far: 95.0
Deduct 35 from 39 and we're left with 4.
Take the next digit (1) from the dividend and append it to 4, then repeat: 41 / 7

Step 4:
When dividing 41 by 7, we get 5 with a remainder of 6.
Use 5 as the next digit of our solution. 
Result so far: 955.0
If we subtract 35 from 41, we get 6.
Append the next digit (5) from the dividend to 6 and continue with: 65 / 7

Moving on to step 5:
65 divided by 7 is 9 with a remainder of 2.
Put 9 as the next digit of the answer. 
Result so far: 9559.0
If we take 63 away from 65, we end up with 2.
Append the next digit (0) from the dividend to 2 and continue with: 20 / 7

Let's proceed to step 6:
The number 7 fits into 20 2 times, leaving a remainder of 6.
The next digit of our result is 2. 
Result so far: 95592.0
If we take 14 away from 20, we end up with 6.
Since there are no more digits in the dividend, we add a zero to the remainder making it 60, and continue the process.

Step 7:
When dividing 60 by 7, we get 8 with a remainder of 4.
The number 8 becomes the next digit in our result. 
Result so far: 95592.8
Deduct 56 from 60 and we're left with 4.
Since there are no more digits in the dividend, we add a zero to the remainder making it 40, and continue the process.

Step 8:
7 can be fit into 40 5 times, resulting in a remainder of 5.
The next digit of our result is 5. 
Result so far: 95592.85
If we take 35 away from 40, we end up with 5.
Since there are no more digits in the dividend, we add a zero to the remainder making it 50, and continue the process.

On to step 9:
If we divide 50 by 7, we get 7 and a remainder of 1.
Put 7 as the next digit of the answer. 
Result so far: 95592.857
Subtracting 49 from 50 leaves us with 1.
Since there are no more digits in the dividend, we add a zero to the remainder making it 10, and continue the process.

Advancing to step 10:
If we divide 10 by 7, we get 1 and a remainder of 3.
The number 1 becomes the next digit in our result. 
Result so far: 95592.8571
If we subtract 7 from 10, we get 3.
Since there are no more digits in the dividend, we add a zero to the remainder making it 30, and continue the process.

Step 11:
7 can be fit into 30 4 times, resulting in a remainder of 2.
The next digit of our result is 4. 
Result so far: 95592.85714
The remainder is 2 after subtracting 28 from 30.
Since there are no more digits in the dividend, we add a zero to the remainder making it 20, and continue the process.

Moving on to step 12:
The number 7 fits into 20 2 times, leaving a remainder of 6.
Put 2 as the next digit of the answer. 
Result so far: 95592.857142
Subtracting 14 from 20 leaves us with 6.
Since there are no more digits in the dividend, we add a zero to the remainder making it 60, and continue the process.

Moving on to step 13:
The number 7 fits into 60 8 times, leaving a remainder of 4.
Write down 8 as next digit of the result. 
Result so far: 95592.8571428
The remainder is 4 after subtracting 56 from 60.
Since there are no more digits in the dividend, we add a zero to the remainder making it 40, and continue the process.

Going ahead to step 14:
If we divide 40 by 7, we get 5 and a remainder of 5.
Use 5 as the next digit of our solution. 
Result so far: 95592.85714285
The remainder is 5 after subtracting 35 from 40.
Since there are no more digits in the dividend, we add a zero to the remainder making it 50, and continue the process.

The final result is 95592.85714285 with a remainder of 5e-09.