582208 ÷ 13 
We want to divide 582208 by 13.

Advancing to step 1:
When dividing 5 by 13, we get 0 with a remainder of 5.
The next digit of our result is 0. 
Result so far: 0.0
Subtract 0 from 5 to get 5.
Fetch the next digit (8) from the dividend, attach it to 5 and continue: 58 / 13

Moving on to step 2:
58 divided by 13 is 4 with a remainder of 6.
The number 4 becomes the next digit in our result. 
Result so far: 4.0
Subtract 52 from 58 to get 6.
Bring next digit (2) of the dividend behind the 6 and repeat the process: 62 / 13

Advancing to step 3:
13 can be fit into 62 4 times, resulting in a remainder of 10.
Use 4 as the next digit of our solution. 
Result so far: 44.0
If we subtract 52 from 62, we get 10.
Take the next digit (2) from the dividend and append it to 10, then repeat: 102 / 13

Advancing to step 4:
13 goes into 102 7 times with a remainder of 11.
The next digit of our result is 7. 
Result so far: 447.0
The remainder is 11 after subtracting 91 from 102.
Fetch the next digit (0) from the dividend, attach it to 11 and continue: 110 / 13

Step 5:
13 goes into 110 8 times with a remainder of 6.
Use 8 as the next digit of our solution. 
Result so far: 4478.0
If we take 104 away from 110, we end up with 6.
Bring next digit (8) of the dividend behind the 6 and repeat the process: 68 / 13

Advancing to step 6:
68 divided by 13 is 5 with a remainder of 3.
Record the quotient 5 as the next digit in the result. 
Result so far: 44785.0
Deduct 65 from 68 and we're left with 3.
Since there are no more digits in the dividend, we add a zero to the remainder making it 30, and continue the process.

Going ahead to step 7:
13 goes into 30 2 times with a remainder of 4.
Use 2 as the next digit of our solution. 
Result so far: 44785.2
If we take 26 away from 30, we end up with 4.
Since there are no more digits in the dividend, we add a zero to the remainder making it 40, and continue the process.

On to step 8:
When dividing 40 by 13, we get 3 with a remainder of 1.
Write down 3 as next digit of the result. 
Result so far: 44785.23
If we take 39 away from 40, we end up with 1.
Since there are no more digits in the dividend, we add a zero to the remainder making it 10, and continue the process.

Moving on to step 9:
13 goes into 10 0 times with a remainder of 10.
Write down 0 as next digit of the result. 
Result so far: 44785.23
Subtracting 0 from 10 leaves us with 10.
Since there are no more digits in the dividend, we add a zero to the remainder making it 100, and continue the process.

Step 10:
13 goes into 100 7 times with a remainder of 9.
Use 7 as the next digit of our solution. 
Result so far: 44785.2307
Deduct 91 from 100 and we're left with 9.
Since there are no more digits in the dividend, we add a zero to the remainder making it 90, and continue the process.

On to step 11:
If we divide 90 by 13, we get 6 and a remainder of 12.
Put 6 as the next digit of the answer. 
Result so far: 44785.23076
Subtract 78 from 90 to get 12.
Since there are no more digits in the dividend, we add a zero to the remainder making it 120, and continue the process.

Let's proceed to step 12:
13 can be fit into 120 9 times, resulting in a remainder of 3.
Use 9 as the next digit of our solution. 
Result so far: 44785.230769
Subtract 117 from 120 to get 3.
Since there are no more digits in the dividend, we add a zero to the remainder making it 30, and continue the process.

Going ahead to step 13:
When dividing 30 by 13, we get 2 with a remainder of 4.
The next digit of our result is 2. 
Result so far: 44785.2307692
If we subtract 26 from 30, we get 4.
Since there are no more digits in the dividend, we add a zero to the remainder making it 40, and continue the process.

Advancing to step 14:
13 goes into 40 3 times with a remainder of 1.
The number 3 becomes the next digit in our result. 
Result so far: 44785.23076923
Subtracting 39 from 40 leaves us with 1.
Since there are no more digits in the dividend, we add a zero to the remainder making it 10, and continue the process.

The quotient of the division is 44785.23076923, and the remainder is 1e-09.