We're dividing 856050 by 7 
We want to figure out the number of times 856050 can be divided by 7.

Advancing to step 1:
7 goes into 8 1 times with a remainder of 1.
Use 1 as the next digit of our solution. 
Result so far: 1.0
If we subtract 7 from 8, we get 1.
Bring next digit (5) of the dividend behind the 1 and repeat the process: 15 / 7

Advancing to step 2:
15 divided by 7 is 2 with a remainder of 1.
Use 2 as the next digit of our solution. 
Result so far: 12.0
Subtracting 14 from 15 leaves us with 1.
Include the next digit (6) from the dividend after 1, then repeat: 16 / 7

Step 3:
The number 7 fits into 16 2 times, leaving a remainder of 2.
Put 2 as the next digit of the answer. 
Result so far: 122.0
Subtracting 14 from 16 leaves us with 2.
Fetch the next digit (0) from the dividend, attach it to 2 and continue: 20 / 7

On to step 4:
When dividing 20 by 7, we get 2 with a remainder of 6.
Write down 2 as next digit of the result. 
Result so far: 1222.0
Subtracting 14 from 20 leaves us with 6.
Grab the next digit (5) from the dividend, add it to 6, then carry on: 65 / 7

Moving on to step 5:
If we divide 65 by 7, we get 9 and a remainder of 2.
Use 9 as the next digit of our solution. 
Result so far: 12229.0
Subtracting 63 from 65 leaves us with 2.
Take the next digit (0) from the dividend and append it to 2, then repeat: 20 / 7

Step 6:
20 divided by 7 is 2 with a remainder of 6.
Put 2 as the next digit of the answer. 
Result so far: 122292.0
If we take 14 away from 20, we end up with 6.
Since there are no more digits in the dividend, we add a zero to the remainder making it 60, and continue the process.

Advancing to step 7:
7 goes into 60 8 times with a remainder of 4.
The number 8 becomes the next digit in our result. 
Result so far: 122292.8
Deduct 56 from 60 and we're left with 4.
Since there are no more digits in the dividend, we add a zero to the remainder making it 40, and continue the process.

On to step 8:
7 can be fit into 40 5 times, resulting in a remainder of 5.
The number 5 becomes the next digit in our result. 
Result so far: 122292.85
Subtract 35 from 40 to get 5.
Since there are no more digits in the dividend, we add a zero to the remainder making it 50, and continue the process.

Step 9:
7 goes into 50 7 times with a remainder of 1.
Write down 7 as next digit of the result. 
Result so far: 122292.857
Subtracting 49 from 50 leaves us with 1.
Since there are no more digits in the dividend, we add a zero to the remainder making it 10, and continue the process.

Let's proceed to step 10:
10 divided by 7 is 1 with a remainder of 3.
Record the quotient 1 as the next digit in the result. 
Result so far: 122292.8571
Deduct 7 from 10 and we're left with 3.
Since there are no more digits in the dividend, we add a zero to the remainder making it 30, and continue the process.

Going ahead to step 11:
The number 7 fits into 30 4 times, leaving a remainder of 2.
Put 4 as the next digit of the answer. 
Result so far: 122292.85714
If we subtract 28 from 30, we get 2.
Since there are no more digits in the dividend, we add a zero to the remainder making it 20, and continue the process.

Advancing to step 12:
7 goes into 20 2 times with a remainder of 6.
Write down 2 as next digit of the result. 
Result so far: 122292.857142
Subtract 14 from 20 to get 6.
Since there are no more digits in the dividend, we add a zero to the remainder making it 60, and continue the process.

Advancing to step 13:
When dividing 60 by 7, we get 8 with a remainder of 4.
Write down 8 as next digit of the result. 
Result so far: 122292.8571428
If we take 56 away from 60, we end up with 4.
Since there are no more digits in the dividend, we add a zero to the remainder making it 40, and continue the process.

Step 14:
When dividing 40 by 7, we get 5 with a remainder of 5.
Record the quotient 5 as the next digit in the result. 
Result so far: 122292.85714285
Subtract 35 from 40 to get 5.
Since there are no more digits in the dividend, we add a zero to the remainder making it 50, and continue the process.

The final outcome is 122292.85714285, with a leftover of 5e-09.