We divide 11795 by 15
Let's see how many times 15 fits into 11795.

Let's proceed to step 1:
The number 15 fits into 1 0 times, leaving a remainder of 1.
Use 0 as the next digit of our solution. 
Result so far: 0.0
Subtracting 0 from 1 leaves us with 1.
Bring next digit (1) of the dividend behind the 1 and repeat the process: 11 / 15

Moving on to step 2:
11 divided by 15 is 0 with a remainder of 11.
Write down 0 as next digit of the result. 
Result so far: 0.0
The remainder is 11 after subtracting 0 from 11.
Include the next digit (7) from the dividend after 11, then repeat: 117 / 15

On to step 3:
15 can be fit into 117 7 times, resulting in a remainder of 12.
Use 7 as the next digit of our solution. 
Result so far: 7.0
Subtract 105 from 117 to get 12.
Take the next digit (9) from the dividend and append it to 12, then repeat: 129 / 15

On to step 4:
15 can be fit into 129 8 times, resulting in a remainder of 9.
The next digit of our result is 8. 
Result so far: 78.0
The remainder is 9 after subtracting 120 from 129.
Bring next digit (5) of the dividend behind the 9 and repeat the process: 95 / 15

Let's proceed to step 5:
95 divided by 15 is 6 with a remainder of 5.
Use 6 as the next digit of our solution. 
Result so far: 786.0
The remainder is 5 after subtracting 90 from 95.
Since there are no more digits in the dividend, we add a zero to the remainder making it 50, and continue the process.

Advancing to step 6:
15 can be fit into 50 3 times, resulting in a remainder of 5.
Put 3 as the next digit of the answer. 
Result so far: 786.3
Subtracting 45 from 50 leaves us with 5.
Since there are no more digits in the dividend, we add a zero to the remainder making it 50, and continue the process.

Moving on to step 7:
When dividing 50 by 15, we get 3 with a remainder of 5.
Put 3 as the next digit of the answer. 
Result so far: 786.33
Subtract 45 from 50 to get 5.
Since there are no more digits in the dividend, we add a zero to the remainder making it 50, and continue the process.

The final outcome is 786.33, with a leftover of 0.005.