110928 divided by 23 
Our goal is to divide 110928 by 23.

Let's proceed to step 1:
23 goes into 1 0 times with a remainder of 1.
Record the quotient 0 as the next digit in the result. 
Result so far: 0.0
Subtract 0 from 1 to get 1.
Append the next digit (1) from the dividend to 1 and continue with: 11 / 23

Step 2:
23 goes into 11 0 times with a remainder of 11.
Put 0 as the next digit of the answer. 
Result so far: 0.0
If we take 0 away from 11, we end up with 11.
Bring next digit (0) of the dividend behind the 11 and repeat the process: 110 / 23

On to step 3:
When dividing 110 by 23, we get 4 with a remainder of 18.
Write down 4 as next digit of the result. 
Result so far: 4.0
The remainder is 18 after subtracting 92 from 110.
Take the next digit (9) from the dividend and append it to 18, then repeat: 189 / 23

Let's proceed to step 4:
189 divided by 23 is 8 with a remainder of 5.
Use 8 as the next digit of our solution. 
Result so far: 48.0
Subtracting 184 from 189 leaves us with 5.
Take the next digit (2) from the dividend and append it to 5, then repeat: 52 / 23

Moving on to step 5:
If we divide 52 by 23, we get 2 and a remainder of 6.
Put 2 as the next digit of the answer. 
Result so far: 482.0
Subtract 46 from 52 to get 6.
Append the next digit (8) from the dividend to 6 and continue with: 68 / 23

Moving on to step 6:
When dividing 68 by 23, we get 2 with a remainder of 22.
Use 2 as the next digit of our solution. 
Result so far: 4822.0
Deduct 46 from 68 and we're left with 22.
Since there are no more digits in the dividend, we add a zero to the remainder making it 220, and continue the process.

On to step 7:
23 can be fit into 220 9 times, resulting in a remainder of 13.
The next digit of our result is 9. 
Result so far: 4822.9
If we subtract 207 from 220, we get 13.
Since there are no more digits in the dividend, we add a zero to the remainder making it 130, and continue the process.

Going ahead to step 8:
The number 23 fits into 130 5 times, leaving a remainder of 15.
Put 5 as the next digit of the answer. 
Result so far: 4822.95
If we subtract 115 from 130, we get 15.
Since there are no more digits in the dividend, we add a zero to the remainder making it 150, and continue the process.

Advancing to step 9:
150 divided by 23 is 6 with a remainder of 12.
Use 6 as the next digit of our solution. 
Result so far: 4822.956
Deduct 138 from 150 and we're left with 12.
Since there are no more digits in the dividend, we add a zero to the remainder making it 120, and continue the process.

Step 10:
23 goes into 120 5 times with a remainder of 5.
Put 5 as the next digit of the answer. 
Result so far: 4822.9565
Subtract 115 from 120 to get 5.
Since there are no more digits in the dividend, we add a zero to the remainder making it 50, and continue the process.

Let's proceed to step 11:
If we divide 50 by 23, we get 2 and a remainder of 4.
Write down 2 as next digit of the result. 
Result so far: 4822.95652
If we subtract 46 from 50, we get 4.
Since there are no more digits in the dividend, we add a zero to the remainder making it 40, and continue the process.

Advancing to step 12:
23 can be fit into 40 1 times, resulting in a remainder of 17.
The number 1 becomes the next digit in our result. 
Result so far: 4822.956521
Subtracting 23 from 40 leaves us with 17.
Since there are no more digits in the dividend, we add a zero to the remainder making it 170, and continue the process.

Advancing to step 13:
23 can be fit into 170 7 times, resulting in a remainder of 9.
Write down 7 as next digit of the result. 
Result so far: 4822.9565217
If we subtract 161 from 170, we get 9.
Since there are no more digits in the dividend, we add a zero to the remainder making it 90, and continue the process.

Going ahead to step 14:
90 divided by 23 is 3 with a remainder of 21.
The next digit of our result is 3. 
Result so far: 4822.95652173
If we subtract 69 from 90, we get 21.
Since there are no more digits in the dividend, we add a zero to the remainder making it 210, and continue the process.

The final outcome is 4822.95652173, with a leftover of 2.1e-08.