579371 ÷ 7 
We want to divide 579371 by 7.

Going ahead to step 1:
The number 7 fits into 5 0 times, leaving a remainder of 5.
Write down 0 as next digit of the result. 
Result so far: 0.0
If we subtract 0 from 5, we get 5.
Append the next digit (7) from the dividend to 5 and continue with: 57 / 7

On to step 2:
If we divide 57 by 7, we get 8 and a remainder of 1.
Record the quotient 8 as the next digit in the result. 
Result so far: 8.0
Subtracting 56 from 57 leaves us with 1.
Grab the next digit (9) from the dividend, add it to 1, then carry on: 19 / 7

On to step 3:
If we divide 19 by 7, we get 2 and a remainder of 5.
The number 2 becomes the next digit in our result. 
Result so far: 82.0
The remainder is 5 after subtracting 14 from 19.
Take the next digit (3) from the dividend and append it to 5, then repeat: 53 / 7

On to step 4:
When dividing 53 by 7, we get 7 with a remainder of 4.
Write down 7 as next digit of the result. 
Result so far: 827.0
Subtracting 49 from 53 leaves us with 4.
Include the next digit (7) from the dividend after 4, then repeat: 47 / 7

Step 5:
When dividing 47 by 7, we get 6 with a remainder of 5.
Record the quotient 6 as the next digit in the result. 
Result so far: 8276.0
The remainder is 5 after subtracting 42 from 47.
Include the next digit (1) from the dividend after 5, then repeat: 51 / 7

Step 6:
If we divide 51 by 7, we get 7 and a remainder of 2.
Write down 7 as next digit of the result. 
Result so far: 82767.0
Subtract 49 from 51 to get 2.
Since there are no more digits in the dividend, we add a zero to the remainder making it 20, and continue the process.

Moving on to step 7:
7 can be fit into 20 2 times, resulting in a remainder of 6.
Use 2 as the next digit of our solution. 
Result so far: 82767.2
Subtracting 14 from 20 leaves us with 6.
Since there are no more digits in the dividend, we add a zero to the remainder making it 60, and continue the process.

Step 8:
The number 7 fits into 60 8 times, leaving a remainder of 4.
The next digit of our result is 8. 
Result so far: 82767.28
Deduct 56 from 60 and we're left with 4.
Since there are no more digits in the dividend, we add a zero to the remainder making it 40, and continue the process.

On to step 9:
40 divided by 7 is 5 with a remainder of 5.
Write down 5 as next digit of the result. 
Result so far: 82767.285
Subtracting 35 from 40 leaves us with 5.
Since there are no more digits in the dividend, we add a zero to the remainder making it 50, and continue the process.

Advancing to step 10:
50 divided by 7 is 7 with a remainder of 1.
Record the quotient 7 as the next digit in the result. 
Result so far: 82767.2857
The remainder is 1 after subtracting 49 from 50.
Since there are no more digits in the dividend, we add a zero to the remainder making it 10, and continue the process.

Going ahead to step 11:
The number 7 fits into 10 1 times, leaving a remainder of 3.
Use 1 as the next digit of our solution. 
Result so far: 82767.28571
Subtracting 7 from 10 leaves us with 3.
Since there are no more digits in the dividend, we add a zero to the remainder making it 30, and continue the process.

Step 12:
30 divided by 7 is 4 with a remainder of 2.
The number 4 becomes the next digit in our result. 
Result so far: 82767.285714
Deduct 28 from 30 and we're left with 2.
Since there are no more digits in the dividend, we add a zero to the remainder making it 20, and continue the process.

Let's proceed to step 13:
The number 7 fits into 20 2 times, leaving a remainder of 6.
Write down 2 as next digit of the result. 
Result so far: 82767.2857142
If we subtract 14 from 20, we get 6.
Since there are no more digits in the dividend, we add a zero to the remainder making it 60, and continue the process.

Step 14:
7 goes into 60 8 times with a remainder of 4.
Put 8 as the next digit of the answer. 
Result so far: 82767.28571428
If we subtract 56 from 60, we get 4.
Since there are no more digits in the dividend, we add a zero to the remainder making it 40, and continue the process.

After the division, we end up with 82767.28571428 and a remainder of 4e-09.