We look at the division of 59066 by 31 
Let's see how many times 31 fits into 59066.

Let's proceed to step 1:
31 can be fit into 5 0 times, resulting in a remainder of 5.
The number 0 becomes the next digit in our result. 
Result so far: 0.0
If we take 0 away from 5, we end up with 5.
Fetch the next digit (9) from the dividend, attach it to 5 and continue: 59 / 31

Let's proceed to step 2:
59 divided by 31 is 1 with a remainder of 28.
Put 1 as the next digit of the answer. 
Result so far: 1.0
If we take 31 away from 59, we end up with 28.
Bring next digit (0) of the dividend behind the 28 and repeat the process: 280 / 31

Let's proceed to step 3:
The number 31 fits into 280 9 times, leaving a remainder of 1.
Write down 9 as next digit of the result. 
Result so far: 19.0
Deduct 279 from 280 and we're left with 1.
Take the next digit (6) from the dividend and append it to 1, then repeat: 16 / 31

Advancing to step 4:
The number 31 fits into 16 0 times, leaving a remainder of 16.
Record the quotient 0 as the next digit in the result. 
Result so far: 190.0
The remainder is 16 after subtracting 0 from 16.
Bring next digit (6) of the dividend behind the 16 and repeat the process: 166 / 31

Moving on to step 5:
The number 31 fits into 166 5 times, leaving a remainder of 11.
Use 5 as the next digit of our solution. 
Result so far: 1905.0
The remainder is 11 after subtracting 155 from 166.
Since there are no more digits in the dividend, we add a zero to the remainder making it 110, and continue the process.

Advancing to step 6:
31 can be fit into 110 3 times, resulting in a remainder of 17.
The next digit of our result is 3. 
Result so far: 1905.3
Subtract 93 from 110 to get 17.
Since there are no more digits in the dividend, we add a zero to the remainder making it 170, and continue the process.

Moving on to step 7:
If we divide 170 by 31, we get 5 and a remainder of 15.
Record the quotient 5 as the next digit in the result. 
Result so far: 1905.35
Subtract 155 from 170 to get 15.
Since there are no more digits in the dividend, we add a zero to the remainder making it 150, and continue the process.

On to step 8:
150 divided by 31 is 4 with a remainder of 26.
Put 4 as the next digit of the answer. 
Result so far: 1905.354
The remainder is 26 after subtracting 124 from 150.
Since there are no more digits in the dividend, we add a zero to the remainder making it 260, and continue the process.

On to step 9:
If we divide 260 by 31, we get 8 and a remainder of 12.
Write down 8 as next digit of the result. 
Result so far: 1905.3548
The remainder is 12 after subtracting 248 from 260.
Since there are no more digits in the dividend, we add a zero to the remainder making it 120, and continue the process.

Going ahead to step 10:
When dividing 120 by 31, we get 3 with a remainder of 27.
The number 3 becomes the next digit in our result. 
Result so far: 1905.35483
Subtracting 93 from 120 leaves us with 27.
Since there are no more digits in the dividend, we add a zero to the remainder making it 270, and continue the process.

Going ahead to step 11:
31 can be fit into 270 8 times, resulting in a remainder of 22.
Write down 8 as next digit of the result. 
Result so far: 1905.354838
The remainder is 22 after subtracting 248 from 270.
Since there are no more digits in the dividend, we add a zero to the remainder making it 220, and continue the process.

Advancing to step 12:
31 can be fit into 220 7 times, resulting in a remainder of 3.
The number 7 becomes the next digit in our result. 
Result so far: 1905.3548387
Subtracting 217 from 220 leaves us with 3.
Since there are no more digits in the dividend, we add a zero to the remainder making it 30, and continue the process.

Step 13:
The number 31 fits into 30 0 times, leaving a remainder of 30.
Record the quotient 0 as the next digit in the result. 
Result so far: 1905.3548387
If we take 0 away from 30, we end up with 30.
Since there are no more digits in the dividend, we add a zero to the remainder making it 300, and continue the process.

After the division, we end up with 1905.3548387 and a remainder of 3e-08.