We're dividing 89162 by 59 
We want to figure out the number of times 89162 can be divided by 59.

Advancing to step 1:
8 divided by 59 is 0 with a remainder of 8.
The next digit of our result is 0. 
Result so far: 0.0
Subtract 0 from 8 to get 8.
Take the next digit (9) from the dividend and append it to 8, then repeat: 89 / 59

Let's proceed to step 2:
59 can be fit into 89 1 times, resulting in a remainder of 30.
The next digit of our result is 1. 
Result so far: 1.0
The remainder is 30 after subtracting 59 from 89.
Fetch the next digit (1) from the dividend, attach it to 30 and continue: 301 / 59

Moving on to step 3:
The number 59 fits into 301 5 times, leaving a remainder of 6.
The next digit of our result is 5. 
Result so far: 15.0
Deduct 295 from 301 and we're left with 6.
Include the next digit (6) from the dividend after 6, then repeat: 66 / 59

Let's proceed to step 4:
59 goes into 66 1 times with a remainder of 7.
Write down 1 as next digit of the result. 
Result so far: 151.0
Deduct 59 from 66 and we're left with 7.
Append the next digit (2) from the dividend to 7 and continue with: 72 / 59

Let's proceed to step 5:
59 goes into 72 1 times with a remainder of 13.
The next digit of our result is 1. 
Result so far: 1511.0
If we take 59 away from 72, we end up with 13.
Since there are no more digits in the dividend, we add a zero to the remainder making it 130, and continue the process.

Step 6:
When dividing 130 by 59, we get 2 with a remainder of 12.
Put 2 as the next digit of the answer. 
Result so far: 1511.2
If we subtract 118 from 130, we get 12.
Since there are no more digits in the dividend, we add a zero to the remainder making it 120, and continue the process.

Going ahead to step 7:
The number 59 fits into 120 2 times, leaving a remainder of 2.
Put 2 as the next digit of the answer. 
Result so far: 1511.22
If we subtract 118 from 120, we get 2.
Since there are no more digits in the dividend, we add a zero to the remainder making it 20, and continue the process.

The final outcome is 1511.22, with a leftover of 0.002.