70169 divided by 3 
Our goal is to divide 70169 by 3.

Step 1:
7 divided by 3 is 2 with a remainder of 1.
Write down 2 as next digit of the result. 
Result so far: 2.0
Deduct 6 from 7 and we're left with 1.
Fetch the next digit (0) from the dividend, attach it to 1 and continue: 10 / 3

Let's proceed to step 2:
If we divide 10 by 3, we get 3 and a remainder of 1.
The next digit of our result is 3. 
Result so far: 23.0
Deduct 9 from 10 and we're left with 1.
Append the next digit (1) from the dividend to 1 and continue with: 11 / 3

On to step 3:
3 goes into 11 3 times with a remainder of 2.
Write down 3 as next digit of the result. 
Result so far: 233.0
Deduct 9 from 11 and we're left with 2.
Grab the next digit (6) from the dividend, add it to 2, then carry on: 26 / 3

Let's proceed to step 4:
If we divide 26 by 3, we get 8 and a remainder of 2.
Use 8 as the next digit of our solution. 
Result so far: 2338.0
Subtract 24 from 26 to get 2.
Bring next digit (9) of the dividend behind the 2 and repeat the process: 29 / 3

Going ahead to step 5:
The number 3 fits into 29 9 times, leaving a remainder of 2.
Record the quotient 9 as the next digit in the result. 
Result so far: 23389.0
The remainder is 2 after subtracting 27 from 29.
Since there are no more digits in the dividend, we add a zero to the remainder making it 20, and continue the process.

Let's proceed to step 6:
When dividing 20 by 3, we get 6 with a remainder of 2.
Use 6 as the next digit of our solution. 
Result so far: 23389.6
The remainder is 2 after subtracting 18 from 20.
Since there are no more digits in the dividend, we add a zero to the remainder making it 20, and continue the process.

Advancing to step 7:
If we divide 20 by 3, we get 6 and a remainder of 2.
Use 6 as the next digit of our solution. 
Result so far: 23389.66
The remainder is 2 after subtracting 18 from 20.
Since there are no more digits in the dividend, we add a zero to the remainder making it 20, and continue the process.

After the division, we end up with 23389.66 and a remainder of 0.002.