Let's divide 994990 by 17
The aim is to understand the frequency of 17 in 994990.

Step 1:
9 divided by 17 is 0 with a remainder of 9.
Use 0 as the next digit of our solution. 
Result so far: 0.0
Deduct 0 from 9 and we're left with 9.
Bring next digit (9) of the dividend behind the 9 and repeat the process: 99 / 17

Step 2:
If we divide 99 by 17, we get 5 and a remainder of 14.
The next digit of our result is 5. 
Result so far: 5.0
Subtracting 85 from 99 leaves us with 14.
Include the next digit (4) from the dividend after 14, then repeat: 144 / 17

Going ahead to step 3:
If we divide 144 by 17, we get 8 and a remainder of 8.
Record the quotient 8 as the next digit in the result. 
Result so far: 58.0
If we subtract 136 from 144, we get 8.
Grab the next digit (9) from the dividend, add it to 8, then carry on: 89 / 17

Going ahead to step 4:
If we divide 89 by 17, we get 5 and a remainder of 4.
Use 5 as the next digit of our solution. 
Result so far: 585.0
Deduct 85 from 89 and we're left with 4.
Grab the next digit (9) from the dividend, add it to 4, then carry on: 49 / 17

On to step 5:
49 divided by 17 is 2 with a remainder of 15.
Record the quotient 2 as the next digit in the result. 
Result so far: 5852.0
If we take 34 away from 49, we end up with 15.
Include the next digit (0) from the dividend after 15, then repeat: 150 / 17

On to step 6:
If we divide 150 by 17, we get 8 and a remainder of 14.
The number 8 becomes the next digit in our result. 
Result so far: 58528.0
Deduct 136 from 150 and we're left with 14.
Since there are no more digits in the dividend, we add a zero to the remainder making it 140, and continue the process.

Step 7:
17 goes into 140 8 times with a remainder of 4.
Put 8 as the next digit of the answer. 
Result so far: 58528.8
If we take 136 away from 140, we end up with 4.
Since there are no more digits in the dividend, we add a zero to the remainder making it 40, and continue the process.

Step 8:
When dividing 40 by 17, we get 2 with a remainder of 6.
Put 2 as the next digit of the answer. 
Result so far: 58528.82
If we subtract 34 from 40, we get 6.
Since there are no more digits in the dividend, we add a zero to the remainder making it 60, and continue the process.

On to step 9:
17 goes into 60 3 times with a remainder of 9.
The next digit of our result is 3. 
Result so far: 58528.823
If we subtract 51 from 60, we get 9.
Since there are no more digits in the dividend, we add a zero to the remainder making it 90, and continue the process.

On to step 10:
The number 17 fits into 90 5 times, leaving a remainder of 5.
Use 5 as the next digit of our solution. 
Result so far: 58528.8235
Subtract 85 from 90 to get 5.
Since there are no more digits in the dividend, we add a zero to the remainder making it 50, and continue the process.

Advancing to step 11:
17 goes into 50 2 times with a remainder of 16.
Use 2 as the next digit of our solution. 
Result so far: 58528.82352
Deduct 34 from 50 and we're left with 16.
Since there are no more digits in the dividend, we add a zero to the remainder making it 160, and continue the process.

Advancing to step 12:
160 divided by 17 is 9 with a remainder of 7.
Record the quotient 9 as the next digit in the result. 
Result so far: 58528.823529
Subtract 153 from 160 to get 7.
Since there are no more digits in the dividend, we add a zero to the remainder making it 70, and continue the process.

Going ahead to step 13:
When dividing 70 by 17, we get 4 with a remainder of 2.
Use 4 as the next digit of our solution. 
Result so far: 58528.8235294
Deduct 68 from 70 and we're left with 2.
Since there are no more digits in the dividend, we add a zero to the remainder making it 20, and continue the process.

Let's proceed to step 14:
The number 17 fits into 20 1 times, leaving a remainder of 3.
Write down 1 as next digit of the result. 
Result so far: 58528.82352941
If we subtract 17 from 20, we get 3.
Since there are no more digits in the dividend, we add a zero to the remainder making it 30, and continue the process.

The final outcome is 58528.82352941, with a leftover of 3e-09.