We divide 49552 by 35
We want to divide 49552 by 35.

Advancing to step 1:
4 divided by 35 is 0 with a remainder of 4.
Record the quotient 0 as the next digit in the result. 
Result so far: 0.0
If we take 0 away from 4, we end up with 4.
Take the next digit (9) from the dividend and append it to 4, then repeat: 49 / 35

On to step 2:
When dividing 49 by 35, we get 1 with a remainder of 14.
The next digit of our result is 1. 
Result so far: 1.0
Deduct 35 from 49 and we're left with 14.
Take the next digit (5) from the dividend and append it to 14, then repeat: 145 / 35

Advancing to step 3:
35 can be fit into 145 4 times, resulting in a remainder of 5.
The number 4 becomes the next digit in our result. 
Result so far: 14.0
Subtract 140 from 145 to get 5.
Include the next digit (5) from the dividend after 5, then repeat: 55 / 35

Moving on to step 4:
If we divide 55 by 35, we get 1 and a remainder of 20.
Record the quotient 1 as the next digit in the result. 
Result so far: 141.0
Subtracting 35 from 55 leaves us with 20.
Include the next digit (2) from the dividend after 20, then repeat: 202 / 35

Step 5:
When dividing 202 by 35, we get 5 with a remainder of 27.
Record the quotient 5 as the next digit in the result. 
Result so far: 1415.0
Subtract 175 from 202 to get 27.
Since there are no more digits in the dividend, we add a zero to the remainder making it 270, and continue the process.

On to step 6:
270 divided by 35 is 7 with a remainder of 25.
The number 7 becomes the next digit in our result. 
Result so far: 1415.7
Subtracting 245 from 270 leaves us with 25.
Since there are no more digits in the dividend, we add a zero to the remainder making it 250, and continue the process.

Step 7:
35 goes into 250 7 times with a remainder of 5.
Put 7 as the next digit of the answer. 
Result so far: 1415.77
The remainder is 5 after subtracting 245 from 250.
Since there are no more digits in the dividend, we add a zero to the remainder making it 50, and continue the process.

The final outcome is 1415.77, with a leftover of 0.005.