We look at the division of 543367 by 13 
We're looking to find how many times 13 goes into 543367.

Going ahead to step 1:
If we divide 5 by 13, we get 0 and a remainder of 5.
Record the quotient 0 as the next digit in the result. 
Result so far: 0.0
Subtracting 0 from 5 leaves us with 5.
Take the next digit (4) from the dividend and append it to 5, then repeat: 54 / 13

Step 2:
When dividing 54 by 13, we get 4 with a remainder of 2.
The number 4 becomes the next digit in our result. 
Result so far: 4.0
If we subtract 52 from 54, we get 2.
Take the next digit (3) from the dividend and append it to 2, then repeat: 23 / 13

Moving on to step 3:
13 goes into 23 1 times with a remainder of 10.
The next digit of our result is 1. 
Result so far: 41.0
If we take 13 away from 23, we end up with 10.
Bring next digit (3) of the dividend behind the 10 and repeat the process: 103 / 13

Step 4:
13 goes into 103 7 times with a remainder of 12.
The next digit of our result is 7. 
Result so far: 417.0
The remainder is 12 after subtracting 91 from 103.
Include the next digit (6) from the dividend after 12, then repeat: 126 / 13

Step 5:
13 goes into 126 9 times with a remainder of 9.
The number 9 becomes the next digit in our result. 
Result so far: 4179.0
Deduct 117 from 126 and we're left with 9.
Bring next digit (7) of the dividend behind the 9 and repeat the process: 97 / 13

Advancing to step 6:
97 divided by 13 is 7 with a remainder of 6.
Put 7 as the next digit of the answer. 
Result so far: 41797.0
If we subtract 91 from 97, we get 6.
Since there are no more digits in the dividend, we add a zero to the remainder making it 60, and continue the process.

Moving on to step 7:
13 can be fit into 60 4 times, resulting in a remainder of 8.
Write down 4 as next digit of the result. 
Result so far: 41797.4
If we subtract 52 from 60, we get 8.
Since there are no more digits in the dividend, we add a zero to the remainder making it 80, and continue the process.

Advancing to step 8:
80 divided by 13 is 6 with a remainder of 2.
The number 6 becomes the next digit in our result. 
Result so far: 41797.46
Subtract 78 from 80 to get 2.
Since there are no more digits in the dividend, we add a zero to the remainder making it 20, and continue the process.

On to step 9:
If we divide 20 by 13, we get 1 and a remainder of 7.
Record the quotient 1 as the next digit in the result. 
Result so far: 41797.461
Deduct 13 from 20 and we're left with 7.
Since there are no more digits in the dividend, we add a zero to the remainder making it 70, and continue the process.

Moving on to step 10:
70 divided by 13 is 5 with a remainder of 5.
Use 5 as the next digit of our solution. 
Result so far: 41797.4615
Subtract 65 from 70 to get 5.
Since there are no more digits in the dividend, we add a zero to the remainder making it 50, and continue the process.

Step 11:
When dividing 50 by 13, we get 3 with a remainder of 11.
Write down 3 as next digit of the result. 
Result so far: 41797.46153
If we subtract 39 from 50, we get 11.
Since there are no more digits in the dividend, we add a zero to the remainder making it 110, and continue the process.

Moving on to step 12:
13 goes into 110 8 times with a remainder of 6.
The next digit of our result is 8. 
Result so far: 41797.461538
Subtracting 104 from 110 leaves us with 6.
Since there are no more digits in the dividend, we add a zero to the remainder making it 60, and continue the process.

Moving on to step 13:
13 goes into 60 4 times with a remainder of 8.
Use 4 as the next digit of our solution. 
Result so far: 41797.4615384
If we subtract 52 from 60, we get 8.
Since there are no more digits in the dividend, we add a zero to the remainder making it 80, and continue the process.

On to step 14:
80 divided by 13 is 6 with a remainder of 2.
Put 6 as the next digit of the answer. 
Result so far: 41797.46153846
Subtract 78 from 80 to get 2.
Since there are no more digits in the dividend, we add a zero to the remainder making it 20, and continue the process.

The quotient of the division is 41797.46153846, and the remainder is 2e-09.