315028 ÷ 37 
We want to figure out the number of times 315028 can be divided by 37.

Moving on to step 1:
3 divided by 37 is 0 with a remainder of 3.
Write down 0 as next digit of the result. 
Result so far: 0.0
Subtract 0 from 3 to get 3.
Grab the next digit (1) from the dividend, add it to 3, then carry on: 31 / 37

Going ahead to step 2:
37 goes into 31 0 times with a remainder of 31.
Put 0 as the next digit of the answer. 
Result so far: 0.0
Subtract 0 from 31 to get 31.
Bring next digit (5) of the dividend behind the 31 and repeat the process: 315 / 37

Going ahead to step 3:
37 can be fit into 315 8 times, resulting in a remainder of 19.
The next digit of our result is 8. 
Result so far: 8.0
If we subtract 296 from 315, we get 19.
Append the next digit (0) from the dividend to 19 and continue with: 190 / 37

Step 4:
190 divided by 37 is 5 with a remainder of 5.
Put 5 as the next digit of the answer. 
Result so far: 85.0
Subtract 185 from 190 to get 5.
Take the next digit (2) from the dividend and append it to 5, then repeat: 52 / 37

On to step 5:
If we divide 52 by 37, we get 1 and a remainder of 15.
Put 1 as the next digit of the answer. 
Result so far: 851.0
If we take 37 away from 52, we end up with 15.
Grab the next digit (8) from the dividend, add it to 15, then carry on: 158 / 37

Step 6:
37 can be fit into 158 4 times, resulting in a remainder of 10.
Use 4 as the next digit of our solution. 
Result so far: 8514.0
If we subtract 148 from 158, we get 10.
Since there are no more digits in the dividend, we add a zero to the remainder making it 100, and continue the process.

Going ahead to step 7:
100 divided by 37 is 2 with a remainder of 26.
Use 2 as the next digit of our solution. 
Result so far: 8514.2
If we subtract 74 from 100, we get 26.
Since there are no more digits in the dividend, we add a zero to the remainder making it 260, and continue the process.

Step 8:
37 can be fit into 260 7 times, resulting in a remainder of 1.
Record the quotient 7 as the next digit in the result. 
Result so far: 8514.27
Deduct 259 from 260 and we're left with 1.
Since there are no more digits in the dividend, we add a zero to the remainder making it 10, and continue the process.

Advancing to step 9:
If we divide 10 by 37, we get 0 and a remainder of 10.
Write down 0 as next digit of the result. 
Result so far: 8514.27
If we take 0 away from 10, we end up with 10.
Since there are no more digits in the dividend, we add a zero to the remainder making it 100, and continue the process.

Step 10:
The number 37 fits into 100 2 times, leaving a remainder of 26.
Write down 2 as next digit of the result. 
Result so far: 8514.2702
Subtract 74 from 100 to get 26.
Since there are no more digits in the dividend, we add a zero to the remainder making it 260, and continue the process.

Going ahead to step 11:
37 can be fit into 260 7 times, resulting in a remainder of 1.
Put 7 as the next digit of the answer. 
Result so far: 8514.27027
Subtract 259 from 260 to get 1.
Since there are no more digits in the dividend, we add a zero to the remainder making it 10, and continue the process.

Going ahead to step 12:
37 goes into 10 0 times with a remainder of 10.
Use 0 as the next digit of our solution. 
Result so far: 8514.27027
Subtract 0 from 10 to get 10.
Since there are no more digits in the dividend, we add a zero to the remainder making it 100, and continue the process.

Going ahead to step 13:
37 can be fit into 100 2 times, resulting in a remainder of 26.
Record the quotient 2 as the next digit in the result. 
Result so far: 8514.2702702
Subtract 74 from 100 to get 26.
Since there are no more digits in the dividend, we add a zero to the remainder making it 260, and continue the process.

On to step 14:
If we divide 260 by 37, we get 7 and a remainder of 1.
The next digit of our result is 7. 
Result so far: 8514.27027027
Subtracting 259 from 260 leaves us with 1.
Since there are no more digits in the dividend, we add a zero to the remainder making it 10, and continue the process.

Our division results in 8514.27027027 with a remaining 1e-09.