We look at the division of 53922 by 37 
We're looking to find how many times 37 goes into 53922.

Let's proceed to step 1:
37 can be fit into 5 0 times, resulting in a remainder of 5.
The number 0 becomes the next digit in our result. 
Result so far: 0.0
If we subtract 0 from 5, we get 5.
Grab the next digit (3) from the dividend, add it to 5, then carry on: 53 / 37

Let's proceed to step 2:
37 can be fit into 53 1 times, resulting in a remainder of 16.
Write down 1 as next digit of the result. 
Result so far: 1.0
Subtracting 37 from 53 leaves us with 16.
Grab the next digit (9) from the dividend, add it to 16, then carry on: 169 / 37

Advancing to step 3:
37 can be fit into 169 4 times, resulting in a remainder of 21.
Use 4 as the next digit of our solution. 
Result so far: 14.0
The remainder is 21 after subtracting 148 from 169.
Append the next digit (2) from the dividend to 21 and continue with: 212 / 37

Advancing to step 4:
37 can be fit into 212 5 times, resulting in a remainder of 27.
Record the quotient 5 as the next digit in the result. 
Result so far: 145.0
Deduct 185 from 212 and we're left with 27.
Take the next digit (2) from the dividend and append it to 27, then repeat: 272 / 37

Moving on to step 5:
The number 37 fits into 272 7 times, leaving a remainder of 13.
Write down 7 as next digit of the result. 
Result so far: 1457.0
The remainder is 13 after subtracting 259 from 272.
Since there are no more digits in the dividend, we add a zero to the remainder making it 130, and continue the process.

Advancing to step 6:
The number 37 fits into 130 3 times, leaving a remainder of 19.
The number 3 becomes the next digit in our result. 
Result so far: 1457.3
Subtracting 111 from 130 leaves us with 19.
Since there are no more digits in the dividend, we add a zero to the remainder making it 190, and continue the process.

Going ahead to step 7:
The number 37 fits into 190 5 times, leaving a remainder of 5.
The number 5 becomes the next digit in our result. 
Result so far: 1457.35
Subtract 185 from 190 to get 5.
Since there are no more digits in the dividend, we add a zero to the remainder making it 50, and continue the process.

On to step 8:
If we divide 50 by 37, we get 1 and a remainder of 13.
Record the quotient 1 as the next digit in the result. 
Result so far: 1457.351
Deduct 37 from 50 and we're left with 13.
Since there are no more digits in the dividend, we add a zero to the remainder making it 130, and continue the process.

Going ahead to step 9:
130 divided by 37 is 3 with a remainder of 19.
The number 3 becomes the next digit in our result. 
Result so far: 1457.3513
Deduct 111 from 130 and we're left with 19.
Since there are no more digits in the dividend, we add a zero to the remainder making it 190, and continue the process.

Advancing to step 10:
37 goes into 190 5 times with a remainder of 5.
Put 5 as the next digit of the answer. 
Result so far: 1457.35135
Subtract 185 from 190 to get 5.
Since there are no more digits in the dividend, we add a zero to the remainder making it 50, and continue the process.

Let's proceed to step 11:
If we divide 50 by 37, we get 1 and a remainder of 13.
Put 1 as the next digit of the answer. 
Result so far: 1457.351351
If we take 37 away from 50, we end up with 13.
Since there are no more digits in the dividend, we add a zero to the remainder making it 130, and continue the process.

Step 12:
The number 37 fits into 130 3 times, leaving a remainder of 19.
Use 3 as the next digit of our solution. 
Result so far: 1457.3513513
If we subtract 111 from 130, we get 19.
Since there are no more digits in the dividend, we add a zero to the remainder making it 190, and continue the process.

Advancing to step 13:
37 can be fit into 190 5 times, resulting in a remainder of 5.
Record the quotient 5 as the next digit in the result. 
Result so far: 1457.35135135
If we subtract 185 from 190, we get 5.
Since there are no more digits in the dividend, we add a zero to the remainder making it 50, and continue the process.

The quotient of the division is 1457.35135135, and the remainder is 5e-09.