We look at the division of 27218 by 18 
Let's see how many times 18 fits into 27218.

On to step 1:
18 can be fit into 2 0 times, resulting in a remainder of 2.
Record the quotient 0 as the next digit in the result. 
Result so far: 0.0
If we take 0 away from 2, we end up with 2.
Grab the next digit (7) from the dividend, add it to 2, then carry on: 27 / 18

Going ahead to step 2:
The number 18 fits into 27 1 times, leaving a remainder of 9.
Use 1 as the next digit of our solution. 
Result so far: 1.0
If we subtract 18 from 27, we get 9.
Append the next digit (2) from the dividend to 9 and continue with: 92 / 18

On to step 3:
92 divided by 18 is 5 with a remainder of 2.
The number 5 becomes the next digit in our result. 
Result so far: 15.0
Subtracting 90 from 92 leaves us with 2.
Grab the next digit (1) from the dividend, add it to 2, then carry on: 21 / 18

On to step 4:
The number 18 fits into 21 1 times, leaving a remainder of 3.
The next digit of our result is 1. 
Result so far: 151.0
Deduct 18 from 21 and we're left with 3.
Bring next digit (8) of the dividend behind the 3 and repeat the process: 38 / 18

Advancing to step 5:
38 divided by 18 is 2 with a remainder of 2.
Record the quotient 2 as the next digit in the result. 
Result so far: 1512.0
If we subtract 36 from 38, we get 2.
Since there are no more digits in the dividend, we add a zero to the remainder making it 20, and continue the process.

Moving on to step 6:
18 goes into 20 1 times with a remainder of 2.
Use 1 as the next digit of our solution. 
Result so far: 1512.1
If we take 18 away from 20, we end up with 2.
Since there are no more digits in the dividend, we add a zero to the remainder making it 20, and continue the process.

Step 7:
If we divide 20 by 18, we get 1 and a remainder of 2.
Record the quotient 1 as the next digit in the result. 
Result so far: 1512.11
Deduct 18 from 20 and we're left with 2.
Since there are no more digits in the dividend, we add a zero to the remainder making it 20, and continue the process.

The final result is 1512.11 with a remainder of 0.002.