SELECT T1.Name ,  T2.Height FROM climber AS T1 JOIN mountain AS T2 ON T1.Mountain_ID  =  T2.Mountain_ID
What are the names of climbers and the corresponding heights of the mountains that they climb?
PRAGMA foreign_keys = ON;

CREATE TABLE "mountain" (
"Mountain_ID" int,
"Name" text,
"Height" real,
"Prominence" real,
"Range" text,
"Country" text,
PRIMARY KEY ("Mountain_ID")
);

CREATE TABLE "climber" (
"Climber_ID" int,
"Name" text,
"Country" text,
"Time" text,
"Points" real,
"Mountain_ID" int,
PRIMARY KEY ("Climber_ID"),
FOREIGN KEY ("Mountain_ID") REFERENCES "mountain"("Mountain_ID")
);

INSERT INTO  "mountain" VALUES (1,"Kibo (Uhuru Pk)","5895","5885","Kilimanjaro","Tanzania");
INSERT INTO  "mountain" VALUES (2,"Mount Kenya (Batian)","5199","3825","Mount Kenya","Kenya");
INSERT INTO  "mountain" VALUES (3,"Mawenzi (Hans Meyer Pk)","5148","850","Kilimanjaro","Tanzania");
INSERT INTO  "mountain" VALUES (4,"Ngaliema / Mt Stanley (Margherita Pk)","5109","3951","Rwenzori","DR Congo Uganda");
INSERT INTO  "mountain" VALUES (5,"Mount Kenya (Lenana)","4985","130","Mount Kenya","Kenya");
INSERT INTO  "mountain" VALUES (6,"Ngaliema / Mt Stanley (Savoia Pk)","4977","110","Rwenzori","Uganda");
INSERT INTO  "mountain" VALUES (7,"Duwoni / Mt Speke (Vittorio Emanuele Pk)","4890","720","Rwenzori","Uganda");


INSERT INTO  "climber" VALUES ("1","Klaus Enders","West Germany","1:13.05.6","15",1);
INSERT INTO  "climber" VALUES ("2","Siegfried Schauzu","West Germany","1:14.56.4","12",1);
INSERT INTO  "climber" VALUES ("3","Hans Luthringhauser","West Germany","1:16.58.0","10",2);
INSERT INTO  "climber" VALUES ("4","Jean Claude Castella","Switzerland","1:17.16.0","8",2);
INSERT INTO  "climber" VALUES ("5","Horst Owesle","West Germany","1:17.22.0","6",2);
INSERT INTO  "climber" VALUES ("6","Georg Auerbacher","West Germany","1:18.14.6","5",3);
INSERT INTO  "climber" VALUES ("7","Arseneus Butscher","West Germany","1:21.35.6","4",5);
INSERT INTO  "climber" VALUES ("8","Charlie Freedman","United Kingdom","1:25.02.8","3",5);
INSERT INTO  "climber" VALUES ("9","L Currie","United Kingdom","1:25.40.6","2",7);
INSERT INTO  "climber" VALUES ("10","Mick Horsepole","United Kingdom","1:27.28.8","1",7);


('Klaus Enders', 5895.0)
('Siegfried Schauzu', 5895.0)
('Hans Luthringhauser', 5199.0)
('Jean Claude Castella', 5199.0)
('Horst Owesle', 5199.0)
('Georg Auerbacher', 5148.0)
('Arseneus Butscher', 4985.0)
('Charlie Freedman', 4985.0)
('L Currie', 4890.0)
('Mick Horsepole', 4890.0)
