
    Given a student's learning pattern sequence over time, find the longest consistent behavioral pattern that reads the same both forward and backward in their learning journey, indicating stable learning preferences that can be reinforced in their personalized curriculum. The learning pattern sequence is represented as a string where each character represents a specific learning behavior or preference type, and the goal is to identify the length of the most extensive symmetric pattern that may occur non-consecutively throughout their learning timeline.
    

    
def lps(str):
    """
    Given a student's learning pattern sequence over time, find the longest consistent behavioral pattern that reads the same both forward and backward in their learning journey, indicating stable learning preferences that can be reinforced in their personalized curriculum. The learning pattern sequence is represented as a string where each character represents a specific learning behavior or preference type, and the goal is to identify the length of the most extensive symmetric pattern that may occur non-consecutively throughout their learning timeline.
    

    """
def lps(str):
    """
    Given a student's learning pattern sequence over time, find the longest consistent behavioral pattern that reads the same both forward and backward in their learning journey, indicating stable learning preferences that can be reinforced in their personalized curriculum. The learning pattern sequence is represented as a string where each character represents a specific learning behavior or preference type, and the goal is to identify the length of the most extensive symmetric pattern that may occur non-consecutively throughout their learning timeline.
    

    """
    n = len(str)
    L = [[0 for x in range(n)] for x in range(n)]
    for i in range(n):
        L[i][i] = 1
    for cl in range(2, n + 1):
        for i in range(n - cl + 1):
            j = i + cl - 1
            if str[i] == str[j] and cl == 2:
                L[i][j] = 2
            elif str[i] == str[j]:
                L[i][j] = L[i + 1][j - 1] + 2
            else:
                L[i][j] = max(L[i][j - 1], L[i + 1][j])
    return L[0][n - 1]