Q: Eddy and Freddy start simultaneously from city A and they travel to City B and City C respectively. Eddy takes 3 hours and Freddy takes 4 hours to complete the journey. If the distance between City A and City B is 570 kms and City A and City C is 300 kms. What is the ratio of their average speed of travel? (Eddy: Freddy)\nOptions:\n(A) 8/3\n(B) 3/8\n(C) 38/15\n(D) 5/8\n(E) 5/3 Let's give some random thoughts before answering.
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Distance traveled by Eddy = 570 km\nTime taken by Eddy = 3 hours\nAverage speed of Eddy = 570/3 = 190 km/hour\nDistance traveled by Freddy = 300 km\nTime taken by Freddy = 4 hours\nAverage speed of Freddy = 300/4 = 75 km/hour\nRatio of average speed of Eddy to Freddy = 190/75 = 38/15
Therefore, the answer is (C).
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