Of the families in City X in 1991, 60 percent owned a personal computer. The number of families in City X owning a computer in 1993 was 20 percent greater than it was in 1991, and the total number of families in City X was 9 percent greater in 1993 than it was in 1991. what percent of the families in City X owned a personal computer in 1993?\nOptions:\n(A) 59%\n(B) 55%\n(C) 63%\n(D) 66%\n(E) 68% Now, let's think a bit. Some random thoughts:
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Say a 100 families existed in 1991 then the number of families owning a computer in 1991 - 60\nNumber of families owning computer in 1993 = 60 * 120/100 = 72\nNumber of families in 1993 = 109\nThe percentage = 72/109 * 100 = 66%.
The final answer: (D).
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