Give stream of consciousness and then the final answer. There are 3 teams each with 5 basket players. How many combinations are there if we were to pick 2 players from the 3 teams such that no team was picked twice?\nOptions:\n(A) 50\n(B) 23\n(C) 75\n(D) 28\n(E) 45
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There are altogether three arrangements, which are we can select two members each from team A and B, each from team A and C, and each from team B and C. For each arrangement, there are altogether 25 possibilities (5*5) since each team has 5 players. So there are a total of 75 possibilities (25*3).
The final answer: (C).
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