Mark went to a store where he spent one-half of his money, and then spent $14 more. He then went to another store where he spent one-third of his starting money, and then spent $16 more. If he then had no money left, how much did he have when he entered the first store? Let's think first. Chain of thought:
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Let X be the money Mark had. Mark spent 1 / 2 * X + 14 in the first store and 1 / 3 * X + 16 in the second store. Mark has X - 1 / 2 * X - 14 - 1 / 3 * X - 16 = $0 left. Combining like terms, we get 1 / 6 * X - 30 = $0. Adding 30 to both sides and multiplying both sides by 6, we find that Mark had X = $180 when he entered the first store.
Therefore, the answer is 180.
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