What is the least value of integer N such that N! is divisible by 888 ?\nOptions:\n(A) 13\n(B) 88\n(C) 31\n(D) 37\n(E) D)  888 OK. Let's think. Some random thoughts first:
User
888 = 8*111 = 3*8*37\nHence 888 is a multiple of 37 and we need at least one 37 in N!\nTherefore least value of N! is 37!, which will contain all of 3, 8, and 37. The answer: (D).
Assistant