Question: If a man walks to his office at 3/4 of his usual rate, he reaches office 1/3 of an hour later than usual. What is his usual time to reach office.\nOptions:\n(A) 1⁄2 hr\n(B) 1 hr\n(C) 3⁄4 hr\n(D) 2 hrs\n(E) None of these Random thoughts:
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If new speed is a⁄b of original speed, then usual time × (b⁄a - 1) = change in time\n∴ usual time × (4⁄3 - 1) = 1⁄3\n⇒ usual time = 1⁄3 × 3 = 1 hr The final answer: (B).
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