Give stream of consciousness and then the final answer. A telephone company needs to create a set of 3-digit area codes. The company is entitled to use only digits 6, 4 and 3, which can be repeated. If the product of the digits in the area code must be even, how many different codes can be created?\nOptions:\n(A) 20\n(B) 22\n(C) 26\n(D) 24\n(E) 30
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Total # of codes possible is 3*3*3 = 27. Oit of those 27 codes only the product of 333 and will be odd, the remaining 26 will have either 2 or 4 in them, which ensures that their product will be even. Therefore the number of codes where the product of the digits is even = (total) - (restriction) = 27 - 1 = 26.
The final answer: (C).
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