There are 3 teams each with 3 basket players. How many combinations are there if we were to pick 2 players from the 3 teams such that no team was picked twice?\nOptions:\n(A) 50\n(B) 23\n(C) 27\n(D) 28\n(E) 45 Let's think first. Stream of consciousness:
User
There are altogether three arrangements, which are we can select two members each from team A and B, each from team A and C, and each from team B and C. For each arrangement, there are altogether 9 possibilities (3*3) since each team has 3 players. So there are a total of 27 possibilities (9*3). I hope this method is easier for you to understand.
So, the answer is (C).
Assistant