From a Group of 10 People, Including George and Nina, 3 people are to be selected at random to work on a certain project. What is the probability that 3 people selected will include George but not Nina\nOptions:\n(A) 5/56\n(B) 9/56\n(C) 28/120\n(D) 21/56\n(E) 25/56 Hmmm, my stream of consciousness:
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Number of ways of selecting 3 people out of 10 people = 10C3\nIn the three members George will always be there in the team. At this step we have vacancy for 2 more members and 9 members are available. Lina cannot be there in the team. So 2 members have to be selected and the number of available members = 9 - Nina = 8\nNumber of ways to form a 3 member team that includes George and excludes Nina = 8C2\nProbability = 8C2/10C3 = 28/120 So, the answer is (C).
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