There are 47 distinct numbers in set M, there are 28 distinct numbers in set N, and there are 12 distinct numbers that are in both sets M and N. Set H is the set containing the elements that are in at least one of sets M and N. How many elements are in set H?\nOptions:\n(A) 39\n(B) 40\n(C) 51\n(D) 58\n(E) 63 Think first, then make a decision. Some random thoughts:
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{Total} = {M} + {N} - {Both}\n{Total} = 47 + 28 - 12 = 63. So the answer is (E).
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