Give stream of consciousness and then the final answer. There are 24 distinct numbers in set M, there are 28 distinct numbers in set N, and there are 12 distinct numbers that are in both sets M and N. Set H is the set containing the elements that are in at least one of sets M and N. How many elements are in set H?\nOptions:\n(A) 39\n(B) 40\n(C) 51\n(D) 58\n(E) 63
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{Total} = {M} + {N} - {Both}\n{Total} = 24 + 28 - 12 = 40.
The final answer: (B).
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