In 2 bags, there are to be put together 5 red and 12 white balls, neither bag being empty. How must the balls be divided so as to give a person who draws 1 ball from either bag-\nOptions:\n(A) 9/18\n(B) 9/16\n(C) 9/11\n(D) 9/12\n(E) 9/13 Think first, then make a decision. Some random thoughts:
User
(1) Put 1 white in first bag, and all the remaining ball in second bag. Probability = 12×0+12×51612×0+12×516 = 532532\n(2) To maximize, we put 1 red in the first bag, and all the remaining in the second. Probability = 12×1+12×43212×1+12×432 = 9/16 So the answer is (B).
Assistant