Train A & B leave from same station and reaches same destination but train A leaves half an after Train B & travels 2 times faster than B. Total distance is 100 miles & train B travels 50 miles/hour. Which train reaches the destination first & what is the time difference between the train\nOptions:\n(A) Train A reaches 30 minutes before Train B\n(B) Train B reaches 30 minutes before Train A\n(C) Train A reaches 60 minutes before Train B\n(D) Train B reaches 60 minutes before Train A\n(E) None of the above OK. Let's think. Some random thoughts first:
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Time taken for train A = 30 minutes + d1/s1 = 30 minutes + 100 / 100 = 1 hours 30 minutes\nSince Train B travels 50 miles / hour ; train A travels twice the speed of B which gives s1 = 100 miles/ hour\nTime taken for train B = d2/s2 = 100 / 50 = 2 Hours\nSo Train A reaches 30 minutes before Train B The answer: (A).
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