Alice, Benjamin, and Carol each try independently to win a carnival game. If their individual probabilities for success are 1/5, 3/8, and 3/7, respectively, what is the probability that exactly two of the three players will win but one will lose?\nOptions:\n(A) 63/280\n(B) 1/280\n(C) 3/56\n(D) 3/35\n(E) 7/40 Stream of consciousness:
User
P = P(A wins, B wins, C loses) + P(A wins, B loses, C wins) + P(A loses, B wins, C wins) = 1/5*3/8*4/7 + 1/5*5/8*3/7 + 4/5*3/8*3/7 = 63/280.
Thus, the answer is (A).
Assistant