Question: From the set of numbers x, y, t, z, p, q and w, how many different combinations can we have without the t in them? Ex:. (x,y), (x), (w,z,y,x,p,q), etc and (x,y)=(y,x)\nOptions:\n(A) 10\n(B) 14\n(C) 45\n(D) 63\n(E) 80 Random thoughts:
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Another way: Any letter (x, y, z, w, p, q) can be included or not. So, we have 2^6 combinations - 1 empty combination = 63 combinations The final answer: (D).
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