If the average (arithmetic mean) of the four numbers K, 2K + 3, 3K – 5 and 5K + 1 is 96, what is the value of K?\nOptions:\n(A)  11\n(B)  15 3/4\n(C)  22\n(D)  35\n(E)  25 3/10 Stream of consciousness first, then make a decision:
User
K + 2K +3 + 3K - 5 + 5K +1 = 11K -1\n(11K -1)/4 = 96\n11K = 96 * 4 +1 = 384 +1 = 385\nK = 385 / 11 = 35.
Thus, the answer is (D).
Assistant