In 1 kg mixture of sand and iron, 20% is iron. How much sand should be added so that the proportion of iron becomes 10%?\nOptions:\n(A) 1 kg\n(B) 200 gms\n(C) 800 gms\n(D) 1.8 kg\n(E) None of these Hmmm, my stream of consciousness:
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In 1 kg mixture quantity of iron = 200 gm\nLet x gm sand should be added, then\n10% of (1000 + x) = 200\n\ x = 1000 gm = 1 kg So, the answer is (A).
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