Some question: Eight friends go to watch a movie but only 5 tickets were available. In how many different ways can 5 people sit and watch the movie?\nOptions:\n(A) 8C5\n(B) 8*7*6*5*4\n(C) 5!\n(D) 8!/5!\n(E) 8*5
Some stream of consciousness:
User
Choosing 5 out of 8, when order matters P58, or choosing 5 out of 8, without order and then arranging: C58∗5! The answer: (B).
Assistant