If n is a natural number, then (6n^2 + 6n) is always divisible by\nOptions:\n(A) 6 only\n(B) 6 and 12 both\n(C) 12 only\n(D) 18 only\n(E) 12 and 18 both Stream of consciousness:
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(6n^2 + 6n) = 6n(n + 1), which is divisible by both 6 and 12, since n(n+1) is always even.
Thus, the answer is (B).
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