From the set of numbers x, y, t, z and w, how many different combinations can we have without the t and z in them? Ex:. (x,y), (x), (w,y,x), etc and (x,y)=(y,x)\nOptions:\n(A) 6\n(B) 14\n(C) 15\n(D) 16\n(E) 30 OK. Let's think. Some random thoughts first:
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Another way: Any letter (x, y, w) can be included or not. So, we have 2^3 combinations - 2 empty combination = 6 combinations The answer: (A).
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