Find the 100th place digit of a number forming from digits 1 to 9 without repeatation and number passes the divisibility test of 11 means difference of sum of alternative digits is 0 or divisible by 11.\nOptions:\n(A) 1\n(B) 2\n(C) 3\n(D) 4\n(E) 5 Think first, then make a decision. Some random thoughts:
User
Largest no is 987652413\nSo digit will be 4 So the answer is (D).
Assistant