A plane flies between 4 cities; A, B, C and D. Passengers board and alight at each airport in every city when it departs and lands, respectively. The distance between city A and city B is 100 miles. The distance between city B and city C is 50 miles more than the distance between city A and city B. The distance between city C and city D is twice the distance between city B and city C. Calculate the total distance between city A and city D. Let's be accurate as possible.
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Since the distance between city A and B is 100 miles, and city B and C are 50 more miles apart than city A and B, then city B and C are 100 + 50 = 150 miles apart. The plane's total flying distance between cities A and C is 100 + 150 = 250 miles. The distance between city C and city D is twice the distance between city B and city C, meaning city C and city D are 2 * 150 = 300 miles apart. The plane flies a distance of 250 + 300 = 550 miles from city A to city D.
The answer: 550.
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