Which of the following is equal to the average (arithmetic mean) of (x+1)^2 and (x-1)^2?\nOptions:\n(A) x^2\n(B) x^2+1\n(C) x^2 +4\n(D) x^2+2x\n(E) x^2+4x Hmmm, my stream of consciousness:
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Avg = [(x+1)^2 + (x-1)^2] / 2\nExpanding and simplifying, (x^2 + 2x + 1 + x^2 -2x + 1 ) / 2 = x^2 + 1 So, the answer is (B).
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