Given 3 lines in the plane such that the points of intersection form a triangle with sides of length 20, 20 and 30, the number of points equidistant from all the 3 lines is\nOptions:\n(A) 1\n(B) 3\n(C) 4\n(D) 0\n(E) 2 Stream of consciousness:
User
4 points are possible in which 1 point is the incentre of the circle and other 3 are excentres
Thus, the answer is (C).
Assistant