Some question: How many digits are in the number 50^8 × 8^3 × 11^3?\nOptions:\n(A) 22\n(B) 20\n(C) 19\n(D) 18\n(E) 17
Some stream of consciousness:
User
Whenever you are asked to find the number of digits, try to bring the number in multiples of 10. This way, we can wasily calculate the umber of 0's through the powers of 10\n50^8 × 8^3 × 11^3 = (5^2*2)^8*2^9*11^3 = 5^16*2^17*11^3 = 2*11^3*10^16 = 2662*10^16\nHence we would have 16 trailing 0's and the three digits from 2662\nTotal digits = 4 + 16 = 20 The answer: (B).
Assistant