Use some thinking to answer the following question. If the average (arithmetic mean) of the four numbers K, 2K + 3, 3K – 5 and 5K + 1 is 118, what is the value of K?\nOptions:\n(A)  11\n(B)  15 3/4\n(C)  22\n(D)  118\n(E)  25 3/10
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K + 2K +3 + 3K - 5 + 5K +1 = 11K -1\n(11K -1)/4 = 118\n11K = 118 * 4 +1 = 472 +1 = 473\nK = 473 / 11 = 43. So the final answer is (D).
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