From the set of numbers x, y, t, z, p, q and w, how many different combinations can we have without the t and w in them? Ex:. (x,y), (x), (p,q,z,y,x), etc and (x,y)=(y,x)\nOptions:\n(A) 10\n(B) 14\n(C) 15\n(D) 16\n(E) 30 Now, let's think a bit. Some random thoughts:
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Another way: Any letter (x, y, z, p, q) can be included or not. So, we have 2^5 combinations - 2 empty combinations = 30 combinations
The final answer: (E).
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