If P(32, 6) = kC (32, 6), then what is the value of k?\nOptions:\n(A) 6\n(B) 32\n(C) 120\n(D) 720\n(E) None OK. Let's think. Some random thoughts first:
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Since 32P6 = k32C6\n⇒ 32/ ( 32-6 ) = k(32/ ( 32-6 )\n⇒k = 6! = 720 The answer: (D).
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