How many five-digit numbers are there, if the two leftmost digits are even, the other digits are odd and the digit 4 cannot appear more than once in the number.\nOptions:\n(A) 1875\n(B) 2000\n(C) 2375\n(D) 2500\n(E) 3875 Stream of consciousness:
User
Number of combo with 4 as first digit + Number of combos with 4 as second digit = 1*4*5*5*5 + 3*5*5*5 = 2375
Thus, the answer is (C).
Assistant