Use some thinking to answer the following question. In wardrobe Marry has 3trousers. One of them is grey the 2nd blue and the 3rd brown. In his wardrobe he also has 4shirts. One of them is grey and the other 3are white. He openshiswardrobe in the dark and pick out one shirt trouser pair without examination the color. What is the likelihood that neither the shirt nor the trouser is grey?\nOptions:\n(A) 1/2\n(B) 2/3\n(C) 3/5\n(D) 4/7\n(E) 4/9
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Probability that trouser is not grey = 2/3\nProbability that shirt is not grey = 3/4\n∴ Required probability = 2/3 x 3/4 = 1/2 So the final answer is (A).
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