Some question: In a bucket there are 3 green balls and 2 yellow balls. What is the probability of drawing at least one green ball when drawing two consecutive balls randomly?\nOptions:\n(A) 16/20\n(B) 9/10\n(C) 2/5\n(D) 3/5\n(E) ½
Some stream of consciousness:
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P(at least one green) = 1 - P(no green, so 2 yellow) = 1- 2/5*1/4 = 9/10. The answer: (B).
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