Lizzy: A mother buys a box of sweets. She kept 1/3 of the sweets and divided the rest between her 3 children. The eldest got 8 sweets while the youngest got half as many. If there are 27 pieces of sweets in the box, how many sweets did the second child gets?.
Me: Hmmm, let me think. I think this is the detailed solution:
User
The mother kept 27 x 1 / 3 = 9 pieces of sweets. So there were 27 - 9 = 18 sweets that were divided between the 3 children. The youngest child got 8 / 2 = 4 sweets. So the eldest and the youngest got a total of 8 + 4 = 12 sweets. Therefore, the second child gets 18 - 12 = 6 sweets. Final answer: 6.
Assistant