 Since \(\emptyset\) and \(\mathbb{N}\) are both (trivially) computable sets, by part i) we have \(\textrm{deg}_T(\emptyset) = \textrm{deg}_T(\mathbb{N}) = \mathbf{0}_T\), unlike the \(m\)-degrees. And also unlike the \(m\)-degrees we have by part ii that \(\textrm{deg}_T(A) = \textrm{deg}_T(\overline{A})\). (For if we can decide \(B\) via an algorithm which uses \(A\) an as oracle, then we can also decide it using \(\overline{A}\) as an oracle by simply swapping the responses obtained in our former algorithm.)