Earlier, we hypothesized a and b to stand in full opposition, where \(a \gt b\) (SW V: 288, ff.). Hence \(S = b\), and S distributes itself over representations a and b. Let the part of S borne by a be called “\(\alpha\)”, and the part borne by b, “\(\beta\)”.[26]  Because \(b = S\), it follows that \(\alpha\) + \(\beta\) = b. Since the inhibition sum S must for each representation stand in inverse proportion to its strength, it follows that \(\alpha\) : \(\beta\) :: b : a (Weiss 1928: 77). These equations allow us to calculate the portions of S that are distributed to representations a and b individually.