  Now,  VC2′  and the statistical condition (3) entail: If prob[v(Sx)=0]=1, then prob[v(Sx′)=1]=1. This, however, contradicts the statistics derived from QM for a state where prob[v(Sx)=0] = 1.[10] In fact, there is a probability of 1/17 that  v(Sx′=0).  So, in a long-run test 1/17 of the spin-1 particles will violate the constraint.