which sounds perfectly acceptable. Example: the trajectory such that \(f_{n} = (n, 0)\), starting from \(f_{0} = (0, 0)\) will have macroscopic velocity 1, as \(f_{n} - f_{0} = (n, 0)\) and, divided by \(n\), this leaves (1, 0). Without going into the details, he then shows that the geometrical structure of all (macroscopic) velocities in such a graph cannot correspond to that of Euclidean space. The reason is quite simple (though the proofs are not): in the graph there will always be singled-out, “special” directions and anisotropy will remain detectable even at the macroscopic level. Therefore a transition from the discrete level to the macroscopic, continuous, Euclidean and isotropic level is excluded. This is a truly interesting result as it casts a shadow on all attempts to use a direct, often rather naive transition from the discrete to the continuous level. At the same time, it pleads in favor of more complex transitions from the microscopic to the macroscopic level, e.g., by taking into account the width of a line.