 As Langton and Lewis (1998) point out, however, this strengthened analysis still fails (see also Lewis 1983a). Given intrinsic properties, such as being a cube, are independent of accompaniment, the extrinsic property of being either a lonely cube or an accompanied non-cube is also independent of accompaniment. Hence, provided the strengthened analysis correctly classifies being a cube as intrinsic, it will falsely classify being either a lonely cube or an accompanied non-cube as intrinsic.