 In the Ellsberg choice, this model will assign \(\alpha(\lfrac{2}{3})\) to \(f_2\) and \((1 - \alpha)(\lfrac{1}{3}) + \alpha(1)\) to \(f_3,\) making these acts disprefered to \(f_1\) and \(f_4,\) respectively, if \(\alpha \lt \lfrac{1}{2}\); preferred to \(f_1\) and \(f_4\) if \(\alpha \gt \lfrac{1}{2}\); and indifferent to \(f_1\) and \(f_4\) if \(\alpha = \lfrac{1}{2}.\)