 This again amounts to multiplying \(p(H)\) by a ratio larger than 1, provided \(p(E)\) isn’t close to 1. So \(p(H\mid E)\) will come out larger than \(p(H)\). Of course, the larger \(\varepsilon\) gets, the weaker the confirmation becomes, befitting the weakness with which \(H\) then predicts \(E\).