  Similarly, \(B\)’s expected payoff is \(\bfrac{2}{3}\). Neither player can improve upon this payoff by deviating from the mixed-strategy equilibrium, given that the other player is playing her end of the equilibrium. This equilibrium is fair, in that it yields the same expected payoff for both players. But it also yields a lower expected payoff for each player than either pure equilibrium, since there is a decent chance that the players’ separate randomizing devices will lead to them to different restaurants.