But now let us add in the relative costs of getting the two codes accepted. Since Code A is fairly simple and relatively undemanding, the cost of getting it accepted is −1. Since Code B is more complicated and demanding, the cost of getting it accepted is −7. So if our comparison of the two codes considers the respective costs of getting them accepted, Code A’s expected value is \(n-1\), and Code B’s is \(n+5-7\). Once we include the respective costs of getting the codes accepted, Code A wins.