Below is the list of tables from the database along with their columns and datatype. Need to generate an accurate SQL query for the question.
Only use the columns present in the respective table. Only use the columns which are required to generate the SQL query. Only use table joins if required and not otherwise.

### Tables ###
TABLE: CREATE TABLE view_unit_status ( apt_id number, apt_booking_id number, status_date time, available_yn others )
TABLE: CREATE TABLE apartment_facilities ( apt_id number, facility_code text )
TABLE: CREATE TABLE apartment_bookings ( apt_booking_id number, apt_id number, guest_id number, booking_status_code text, booking_start_date time, booking_end_date time )
TABLE: CREATE TABLE apartment_buildings ( building_id number, building_short_name text, building_full_name text, building_description text, building_address text, building_manager text, building_phone text )
TABLE: CREATE TABLE apartments ( apt_id number, building_id number, apt_type_code text, apt_number text, bathroom_count number, bedroom_count number, room_count text )
TABLE: CREATE TABLE guests ( guest_id number, gender_code text, guest_first_name text, guest_last_name text, date_of_birth time )

### Question ###
Show the facility codes of apartments with more than 4 bedrooms.

### Accurate SQL ###

SELECT T1.facility_code FROM apartment_facilities AS T1 JOIN apartments AS T2 ON T1.apt_id = T2.apt_id WHERE T2.bedroom_count > 4